A bag contains 15 dark chocolates, 16 caramel chocolates, and 19 milk chocolates. The probability that Amber’s teacher distributes the chocolates among her students is 0.4. If the teacher offers Amber a chocolate from the bag, the probability that she randomly picks either a caramel chocolate or a dark chocolate is___________

QUESTION POSTED AT 14/01/2020 - 03:05 PM

Answered by admin AT 14/01/2020 - 03:05 PM

The answer is 31/125 ≈ 0.25.

To calculate this, we will use both addition rule and multiplication rule.
The addition rule is used to calculate the probability of one of the events from multiple pathways. If you want that only one of the events happens, you will use the addition rule. In this method, the possibilities of each event are added. So, we will use the addition rule to calculate the probability that the teacher randomly picks either a caramel chocolate (1st event) or a dark chocolate (2nd event):
1. There are 16 caramel chocolates out of 50 chocolates in total. Thus, the probability that a caramel chocolate is picked is 16/50.
2. There are 15 chocolates out of 50 chocolates in total. Thus, the probability that a caramel chocolate is picked is 15/50.
ADDITION RULE:
16/50 + 15/50 = 31/50
The probability that teacher 
picks either a caramel chocolate or a dark chocolate is 31/50.

The multiplication rule calculates the probability that both of two events will occur. In this method, the possibilities of each event are multiplied. So, we will use the multiplication rule to calculate the probability that the teacher distributes the chocolates among students (1st event) and that  she randomly picks either a caramel chocolate or a dark chocolate (2nd event):

1. The probability that the teacher distributes the chocolates  among students is 0.4 = 4/10.

2. The probability that teacher picks either a caramel chocolate or a dark chocolate is 31/50.

MULTIPLICATION RULE:

4/10 × 31/50 = 124/500 = 31/125 ≈ 0.25

Post your answer

Related questions

What is the sale price of a cell phone that is on sale for 15% off if the regular price is $75?. . . A.$60.00. B.$63.75. C. $64.25. .

The sale price would be 58.75.
If the retail value is $75 with a 15% discount, which the discount is $11.25, it's sale price would be $58.75.

ANSWERED AT 21/01/2020 - 10:48 AM


QUESTION POSTED AT 21/01/2020 - 10:48 AM

1.Write the equation of the line parallel to the line 10x - 5y = 8 and passing through the point (2,4).. 2.Write the equation of the line parallel to the line 4x + 2y = 5 and passing through the point (-3,5).. 3.Write the equation of the line parallel to the line 4x + y = -1 and passing through the point (5,0).. 4.Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).. 5.Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).. . a.y = -5x + 15. b.y = 2x. c.y = -3x + 14. d.y = -2x

1.) Parallel to 10x - 5y = 8 ; (2,4)

10x - 5y = 8
5y = 10x - 8
y = 2x - 8/5
m = 2

y - 4 = 2(x - 2)
y - 4 = 2x - 4
y = 2x

2.) Parallel to 4x + 2y = 5 ; (-3,5)

4x + 2y = 5
2y = -4x + 5
y = -2x - 5/2
m = -2

y - 5 = -2(x + 3)
y - 5 = -2x - 6
y = -2x -1

3.) Parallel to 4x + y = -1 ; (5,0)

4x + y = -1
y = -4x - 1
m = -4

y - 0 = -4(x - 5)
y = -4x + 20

4.) Perpendicular to x - 5y = -10 ; (2,5)

x - 5y = -10
5y = x + 10
y = x/5 - 2
m = -5

y - 5 = -5(x - 2)
y - 5 = -5x + 10
y = -5x + 15

5.) Perpendicular to x - 3y = 9 ; (3,5)

x - 3y = 9
3y = x - 9
y = x/3 - 3
m = -3

y - 5 = -3(x - 3)
y - 5 = -3x + 9
y = -3x + 14

ANSWERED AT 21/01/2020 - 10:48 AM


QUESTION POSTED AT 21/01/2020 - 10:48 AM

A system of equations is shown below:. . 6x – 2y = 3->(equation 1). 5x + 3y = 4->(equation 2). . A student wants to prove that if equation 2 is kept unchanged and equation 1 is replaced with the sum of equation 1 and a multiple of equation 2, the solution to the new system of equations is the same as the solution to the original system of equations. If equation 2 is multiplied by 1, which of the following steps should the student use for the proof?

From my research, the question had contained the following choices:

Show that the solution to the system of equations 10x + y = 7 and 5x + 3y = 4 is the same as the solution to the given system of equations
 
Show that the solution to the system of equations 10x – 2y = 7 and 5x + 3y = 4 is the same as the solution to the given system of equations
 
Show that the solution to the system of equations 11x – y = 7 and 5x + 3y = 4 is the same as the solution to the given system of equations
 
Show that the solution to the system of equations 11x + y = 7 and 5x + 3y = 4 is the same as the solution to the given system of equations

Since all of the 2nd second equations of the choices are the same, we will ignore that. What we will do however, is to obtain the 1st equation of each choice and subtract it from the 1st given equation, and see if it is a multiple to the 2nd given equation. To show an example, let us take the equation in choice D:

11x + y = 7
6x – 2y = 3
_________
5x + 3y = 4

As we can see, it is a multiple of the second given equation. Therefore, the correct answer is choice D.

ANSWERED AT 21/01/2020 - 10:46 AM


QUESTION POSTED AT 21/01/2020 - 10:46 AM

A school district needs to arrange transportation for at least 360 students for a field trip. The district can use large buses or small buses. The large buses hold 60 students each and have an operating expense of $300 for the day. The small buses hold 45 students each and have an operating expense of $200 for the day. The district only has chaperones for, at most, seven buses. What is the minimum cost for the transportation for the field trip?. A.$1,400. B. $1,600. C.$1,700. D.$1,800

Answer:

$1700

Step-by-step explanation:

Let the number of large buses be x

Let number of small buses be y

Let C be the total cost for the trip

Since w eare given that cost of 1 large bus is 300 and 1 small bus is 200

So, Cost C  = 300 * number of large buses + 200 * number of small buses

So  C = 300 x + 200 y

Constraints are :

Since we are given that large buses can hold 60 students each

So, total students in x buses = 60 x

We are also given that small buses can hold 45 students each.

So, total students in y buses = 45y

Since we are also given that A school district needs to arrange transportation for at least 360 students

So, 60x+45y\geq 360

Number of large busesx\geq 0

Number of small buses y\geq 0

We are also given that The district only has chaperones for, at most, seven buses.

So, x+y\leq 7

Now we graph the constraints and find all the endpoints

Refer the attached Graph

So,End points are (3,4) , (6,0) and (7,0)

Now substitute these points in Cost function to find minimum cost.

with(3,4)

C = 300(3) + 200(4)

C = 1700

with (6,0)

C = 300(6) + 200(0)

C = 1800

With (7,0)

C = 300(7) + 200(0)

C = 2100

Hence the minimum cost is $1700.

ANSWERED AT 21/01/2020 - 10:45 AM


QUESTION POSTED AT 21/01/2020 - 10:45 AM

The number of music CDs sold weekly by a store follows a normal distribution with a mean of 455 and a standard deviation of 65. Which sentence summarizes this information?. . A.There is an 84% chance that the shop sells more than 390 CDs in a week. . B.There is a 34% chance that the shop sells more than 390 CDs in a week.. C.There is a 34% chance that the shop sells fewer than 390 CDs in a week.. D.There is a 68% chance that the shop sells fewer than 390 CDs in a week.. E.There is a 95% chance that the shop sells more than 390 CDs in a week.

Answer:

A. There is an 84% chance that the shop sells more than 390 CDs in a week.

Step-by-step explanation:

The number of music CDs sold weekly by a store follows a normal distribution with a mean of 455 and a standard deviation of 65.

Hint- First we will have to calculate the z score and then using z score table we can calculate the probability or area below that point.

Z score can be calculated by the following formula,

Z=\dfrac{X-\mu}{\sigma}

Where,

X = the raw score,

μ = mean of the sample

σ = standard deviation,

Putting the values,

Z=\dfrac{390-455}{65}=-1

From the z score table, we get

P(z<-1)=0.1586=15.86\%\approx 16\%

As from the table we get the probability less than the point which in case is 390 with z score of -1, the probability more with z score more than -1, is

=100-16=84\%


ANSWERED AT 21/01/2020 - 10:42 AM


QUESTION POSTED AT 21/01/2020 - 10:42 AM

The diagonals of parallelogram ABCD intersect at point E. If DE=2X+2,BE=3X-8 ,CE=4y , and AC=32, solve for x.. . A.. x = 2. B.. x = 10. C.. x = 15. D.. x = 22.

the diagonals bisect eachother. 2x+2 = 3x -8 and 4y = 1/2 (32)
x - 8 = 2
x=10

ANSWERED AT 21/01/2020 - 10:42 AM


QUESTION POSTED AT 21/01/2020 - 10:42 AM

A solid has faces that consist of 4 triangles, 3 rectangles, and 1 hexagon. The solid has 9 vertices. How many edges does the solid have?. A.. 12 edges. B.. 15 edges. C.. 18 edges. D.. 21 edges.

Drawing this solid may be hard. Basing on the given description, a solid with nine vertices and having faces consisting of four triangles, three rectangles and one hexagon (polygon with six sides) would have a number of edges around twelve edges. Hence, letter A. 

ANSWERED AT 21/01/2020 - 10:40 AM


QUESTION POSTED AT 21/01/2020 - 10:40 AM

Can segments with lengths of 15, 20, and 36 form a triangle? If so, would the triangle be acute, right, or obtuse?

I believe that the most fitting answer for this question would be that sides of this length cannot form a triangle. The two shorter sides, 15 and 20, would have to be greater than 36 when added together, and they only equal 35. So, since they cannot form a triangle, you would not need to worry about what kind of triangle they would form. Hope this helps.

ANSWERED AT 21/01/2020 - 10:39 AM


QUESTION POSTED AT 21/01/2020 - 10:39 AM

Jane , Andre and Maria picked 840 pounds of apples. Andre picked 3 times as many as Maria. Jane picks 2 times as many as Andre. How many pounds did Andre pick..

To answer the problem, let x be the number of apples Maria picked. By this representation, the number of apples Andre picked is 3x and that Jane picked 6x apples. The sum of all apples picked is 840. The equation that represent the situation is,
 
                                 x + 3x + 6x = 840   ; x = 84 

Andre picked 3x apples. Thus, Andre picked 252 apples. 

ANSWERED AT 21/01/2020 - 10:37 AM


QUESTION POSTED AT 21/01/2020 - 10:37 AM

The test to detect the presence of the hepatitis B virus is 97% accurate for a person who has the disease and 99% accurate for a person who does not have the disease. If 0.55% of the people in a given population are infected, what is the probability that a randomly chosen person gets an incorrect result?. . 0.98455. . 0.000165. . 0.009945. . 0.001011

The probability tests to detect the presence of hepatitis B:
P (presence)= 0.97 (true)  0.03 (false)
P (absence)= 0.99 (true)  0.01 (false)

P(infected)=0.0055
P(not infected)= 0.9945

To have an incorrect result:
P[infected and false from P(presence)] + P[not infected and false from P(absence)]

=0.0055*0.03+0.9945*0.01= 0.01011

The answer is 0.01011 

ANSWERED AT 21/01/2020 - 10:35 AM


QUESTION POSTED AT 21/01/2020 - 10:35 AM

A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant?

Forming thw diagram, you have the length of the hypotenuse, and you want to find the height, which is the 'opposite length to the angle'

So using SOHCAHTOA we have:
sin15 = height / 3000
height = 3000 sin 15 height  = 776.46m

So, the height of the plane above the ground at this instant is 776.46m

ANSWERED AT 21/01/2020 - 10:34 AM


QUESTION POSTED AT 21/01/2020 - 10:34 AM

In a random sample of 50 undergraduate students at a college, it was found that 44 students regularly access social networking websites from their college library. What is the margin of error for the true proportion of all undergraduates who access social networking sites from their college library?

sqrt(pq/n)
p and q generally represent the proportion of success to failure; and n is the sample size
lets define them first.
it tells us that we have 50 students, and 44 are our success rate: p = 44/50 our q (our fail rate) is 0.88
then p = .88, q must equal 1-0.88
p = .88, q = .12, and n = 50
from this we can calcuate:
sqrt(pq/n)=sqrt (0.88x0.12x50)
               =2.29

ANSWERED AT 21/01/2020 - 10:33 AM


QUESTION POSTED AT 21/01/2020 - 10:33 AM

When 100 mL of an aqueous solution containing 1.0 g of caffeine is extracted with 10 mL of chloroform at room temperature, 0.5 g of caffeine is transferred to the chloroform layer. Calculate the distribution coefficient of caffeine between chloroform and water at room temperature.

The distribution coefficient is simply the ratio of the concentrations of the solute in the two solvents.


In this case there is 0.5g of caffeine in 10 ml of chloroform and 0.5 g of caffeine in 100ml of water.


The ratio is 0.5/10 : 0.5/100 = 0.05 : 0.005 = 10 : 1

ANSWERED AT 21/01/2020 - 10:33 AM


QUESTION POSTED AT 21/01/2020 - 10:33 AM

The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almanac, 2009): critical reading-502; mathematics-515; writing-494; Assume that the population standard deviation on each part of the test is = 100.. What is the probability a random sample of 90 test takers will provide a sample mean test score within 10 points of the population mean of 515 on the Mathematics part of the test (to 4 decimals)?

A. P(492 < x-bar < 512) 

z = (492-502)/100/√90 

z = -0.95 is 0.1711 

z = (512-502)/100/√90 

z = 0.95 is 0.8289 

b. P(505 < x-bar < 525) 

z = (505-515)/100/ √90 

z = -0.95 

z = (525-515)/100/ √90 

z = 0.95 

P(-0.95< z < 0.95) = 0.6578 

P(-0.95< z < 0.95) = 0.6578 

c. P(484 < x-bar < 504) 

z = (484-494)/100/√100 

z = -1 is 0.1587 

z = (504-494)/100/√100 

z = 1 is 0.8413 

P(-1< z <1) = 0.6826

ANSWERED AT 21/01/2020 - 10:29 AM


QUESTION POSTED AT 21/01/2020 - 10:29 AM

The diagonal of a TV is 30 inches long. Assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact length and width of the TV?. A. 15 inches by 15/3 inches. B. 15/2 inches by 15/2 inches . C. 60 inches by 60/3 inches . D. 60/2 inches by 60/2 inches

Let

x-------> the length of the rectangle

y------> the width of the rectangle

d----> the diagonal of the rectangle

we know that

The diagonal forms a pair of 30-60-90 right triangles

Step 1

Find the value of y

sin(30)=\frac{y}{d}

Solve for y

y=sin(30)*d

we have

sin(30)=\frac{1}{2}\\\\d=30\ in

substitute

y=\frac{1}{2} *30=15\ in

Step 2

Find the value of x

cos(30)=\frac{x}{d}

Solve for x

x=cos(30)*d

we have

cos(30)=\frac{\sqrt{3}}{2}\\\\d=30\ in

substitute

x=\frac{\sqrt{3}}{2}*30=15\sqrt{3}\ in

therefore

the answer is

15\ inches by 15\sqrt{3}\ inches


ANSWERED AT 21/01/2020 - 10:28 AM


QUESTION POSTED AT 21/01/2020 - 10:28 AM

What is the correct classification of 23x + 16?

The given expression can be classified in many ways. To summarize, there are a few ways to classify it:

It is a polynomial
classification by the number of terms: binomial
classification by degree: first degree polynomial or degree = 1
classification by graph: straight line or a linear function

ANSWERED AT 21/01/2020 - 10:26 AM


QUESTION POSTED AT 21/01/2020 - 10:26 AM

In a random sample of 70 people, it was found that 44 of them were fans of the New York Yankees. What is the margin of error for the true proportion of all individuals who are fans of the New York Yankees?. A. 0.0088 . B. 0.058. C. 0.063. D. 0.116. E. 0.173

The general formula for the margin of error would be:

z * √[p (1-p) ÷ n]

where:
z = values for selected confidence level
p = sample proportion
n = sample size

Since the confidence level is not given, we can only solve for the 
√[p (1-p) ÷ n]  part.

p = 44/70
n = 70

√[44/70 (1 - (44/70) ÷ 70]

√[0.6286 (0.3714)] ÷ 70

√0.2335 ÷ 70

√0.0033357 = 0.05775 or 0.058 Choice B.



ANSWERED AT 21/01/2020 - 10:25 AM


QUESTION POSTED AT 21/01/2020 - 10:25 AM

A water park charges $6 for admission and $1.50 for each ride ticket. You have $36. How many ride tickets can you buy? Graph your solution.. A.x<=30. tickets. . B.x<=20. tickets. . C.x<=15. tickets. . D.x<=10. tickets.

Answer:

x ≤ 20

B is correct.

Step-by-step explanation:

A water park charges $6 for admission and $1.50 for each ride ticket.

Let we take x number of rides.

Total charges for rides and admission fees

Total charges  = 6 + 1.5n

We have only $36

So, Total charges should be less than 36  

Equation:

6 + 1.5x ≤ 36

Now, we will solve for x

   1.5x ≤ 30

      x ≤ 20

So, We can take maximum 20 ride.

Now we make graph of solution. Please find attachment for graph.

ANSWERED AT 21/01/2020 - 10:16 AM


QUESTION POSTED AT 21/01/2020 - 10:16 AM

Renee can sew a 25-square-foot quilt in 16 hours. Genera can sew the same size quilt in 12 hours. How long would it take them to sew the quilt working together?

First let us say that if a 25-square-foot quilt is done that is counted as 1 job. So the rate of Renee is 1 job/16 hours. The rate of Genera is 1/12. To solve the time to finish one job when both are working, we represent it with an algebraic expression as follows: 

 \frac{1}{16} + \frac{1}{12} = \frac{1}{x}

Then x = 6 6/7 hours. 

ANSWERED AT 21/01/2020 - 10:14 AM


QUESTION POSTED AT 21/01/2020 - 10:14 AM

Aidan drives to school and back each day. The school is 16 miles from his home. He averages 40 miles per hour on his way to school. If his total trip takes 1 hour, at approximately what speed does Aidan drive home?

First we have to answers stand that speed is equivalent to the distance traveled in a certain time span. That is speed = distance/time. Conversely, time = distance/speed. We are asked to find the speed going home given, distance, total time and speed going to school. We can answer this equation by adding the time Aidan is spending going and coming back from school 

t = (distance to school)/(speed to school) + (distance to home)/(speed to home)

1hour = (16)/(40) + (16)/(speed to home) 

Speed to home = 26.67miles/hour 

ANSWERED AT 21/01/2020 - 10:14 AM


QUESTION POSTED AT 21/01/2020 - 10:14 AM

The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party, and then returned the purchase? This is called a one-time fling. About 15% of all adults deliberately do a one-time fling and feel no guilt about it! In a group of seven adult friends, find the following probabilities.. (a) No one has done a one-time fling. (Use 3 decimal places.). (b) At least one person has done a one-time fling. (Use 3 decimal places.). . ( c) No more than two people have done a one-time fling. (Use 3 decimal places.)

(a). The probability that no one has done one time fling is \boxed{\bf 0.377}.

(b). The probability that at least one person has done one time fling is \boxed{\bf 0.623}.

(c). The probability that no more than two person has done one time fling is \boxed{\bf 0.98279}.

Further explanation:

Given:

If a person purchased an article of clothing and worn the cloths once then returned the clothes this is known as one time fling.

About 15\% adults do one time fling.

Concept used:

The probability of an event E can be calculated as follows:

\boxed{P(E)=\dfrac{n(E)}{n(S)}}

Here, n(E) is the number of favorable outcomes in an event E and n(S) is the number of element in sample space S.

The probability of exactly r success in n trial can be expressed as follows:

\boxed{P(F)=^{n}C_{r}p^{r}q^{n-r}}

Here, p is the probability of success in an event and q is the probability of failure.

Calculation:

Part (a):

The probability that adults do one time fling is 0.15.

The probability that no adult do one time fling is calculated as follows:

\boxed{1-0.15=0.85}

There are 7 adult friends in a group.

Consider A as an event that no one has done one time fling in a group of seven friends and P(A) as the probability of an event A.

The probability P(A) can be calculated as follows:

\begin{aligned}P(A)&=^7C_{0}\cdot (0.15)^{0} \cdot (0.15)^{7-0}\\&=\dfrac{7!}{0!\cdot 7!}\cdot 1\cdot (0.85)^{7}\\&=1\cdot 1\cdot 0.377\\&=0.377\end{aligned}

Therefore, the probability P(A) is \boxed{\bf 0.377}.

Part (b):

Consider A' as a complement event of an event A.

The complement of event A is the event that at least one person has done one time fling in a group of 7 friends.

The probability of event A' can be calculated as follows:

\boxed{P(A')=1-P(A)}      …… (1)

Substitute P(A)=0.377 in the equation (1) to obtain the probability   as follows:

\begin{aligned}P(A')&=1-0.377\\&=0.623\end{aligned}  

Therefore, the probability that at least one person has done one time fling in a group of 7 friends is \boxed{\bf 0.623}.

Part (c):

The probability that no one has done one time fling is 0.377.

Consider B as an event that one person has done one time fling in a group of seven friends and P(B) as the probability of an event B.

The probability P(B) can be calculated as follows:

\begin{aligned}P(B)&=^7C_{1}\cdot (0.15)^{1} \cdot (0.85)^{7-1}\\&=\dfrac{7!}{1!\cdot 6!}\cdot (0.15) \cdot (0.85)^{6}\\&=\dfrac{7!}{6!}\cdot 0.15 \cdot 0.37714\\&=7\cdot 0.0565\\&=0.396\end{aligned}

 

Consider C as an event that exactly two person has done one time fling in a group of seven friends and P(C) as the probability of an event C.

The probability P(C) can be calculated as follows:

\begin{aligned}P(C)&=^7C_{2}\cdot (0.15)^{2} \cdot (0.85)^{7-2}\\&=\dfrac{7!}{2!\cdot 5!}\cdot (0.15)^{2}\cdot (0.85)^{5}\\&=\dfrac{7\cdot 6}{2}\cdot 0.0225\cdot 0.444\\&=21\cdot 0.00999\\&=0.20979\end{aligned}  

Now, the probability that no more than two person has done one time fling in a group of 7 friends can be calculated as follows:

\boxed{P(X)=P(A)+P(B)+P(C)}         …… (2)

Substitute P(A)=0.377, P(B)=0.396 and P(C)=0.209 in the equation (1) to obtain the probability P(X) as follows:

\begin{aligned}P(X)&=0.377+0.396+0.20979\\&=0.98279\end{aligned}

Therefore, the probability that no more than two person has done one time fling is \boxed{\bf 0.98279}.

Learn more:

1. Learn more about problem on numbers: brainly.com/question/1852063

2. Learn more about problem on function brainly.com/question/3225044

Answer details:

Grade: Senior school

Subject: Mathematics

Chapter: Probability

Keywords: Probability, exact event, sample space, number of element, complement event, success, failure, favorable, trial, one time fling, clothes, person, P(E)=n(E)/n(S).

ANSWERED AT 21/01/2020 - 10:13 AM


QUESTION POSTED AT 21/01/2020 - 10:13 AM

Miranda bought some apples and oranges at the store for fruit salad. Owen bought three times as many apples and twice as many oranges. Miranda has 5 fruits in her bag, but Owen has 12 fruits in his bag. How many apples did Miranda purchase? . . A. 1 . . B. 2 . .C. 3 . .D. 5 .

To answer the question above, let x and y be the number of apples and oranges Miranda bought, respectively.

For Miranda's case, the total number of fruits she bought is 5.
 
                                 (1)           x + y = 5

The number of fruits Owen bought can also be represented by the equation,
 
                                  (2)          3x + 2y = 12

Solving for x and y from the two equations give x = 2 and y = 3. Therefore, the answer is letter B. Miranda bought 2 apples. 

ANSWERED AT 21/01/2020 - 10:13 AM


QUESTION POSTED AT 21/01/2020 - 10:13 AM

The spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed. Which statement is true?. a. A. . . The mean of data set X is greater than the mean of data set Y. . . . . B. . The median of data set X is less than the median of data set Y.. . . . . C. . The standard deviation of data set X is greater than the standard deviation of data set Y.. . . . . D. . The range of data set X is less than the range of data set Y.. . . . . E. . The mode of data set X is greater than the mode of data set Y

Answer: C. . The standard deviation of data set X is greater than the standard deviation of data set Y.

Step-by-step explanation:

We know that the greater spread out a data distribution has greater standard deviation.

Given: The spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed.

Then , The standard deviation of data set X is greater than the standard deviation of data set Y.

ANSWERED AT 21/01/2020 - 10:10 AM


QUESTION POSTED AT 21/01/2020 - 10:10 AM

A cone has a volume of 5 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?. . a. 15 in3. b. 20 in3. c. 25 in3. d. 30 in3

Volume of a cone: (1/3)*(PI)*(r^2)*h
5=(1/3)*(PI)*(r^2)*h
(r^2)*h=4.774648
Volume of the cylinder outside the cone: (PI)*(r^2)*h
V=(PI)*4.774648
V=15 in3

The answer is A. 15 in3

ANSWERED AT 21/01/2020 - 10:10 AM


QUESTION POSTED AT 21/01/2020 - 10:10 AM

If some one gave you 150 dollars and you spent it but owed 15% back what would be that 15%?

15% of 150$ is 22.50 s

ANSWERED AT 21/01/2020 - 09:58 AM


QUESTION POSTED AT 21/01/2020 - 09:58 AM

A basket contains 6 pieces of paper numbered from 1 to 6. A hat contains the letters A, B, and C. If a blindfolded person picks a number and a letter, what is the probability that the number is even and the letter is A?

The two events are independent, so the probability of both happening is the product of the two.

Probability of picking an even number is 3/6=1/2
Probability of picking the letter A is 1/3 = 1/3

Product of probability of two independent events = (1/2)(1./3)=1/6.

ANSWERED AT 21/01/2020 - 09:51 AM


QUESTION POSTED AT 21/01/2020 - 09:51 AM