A line has a slope of - 4/5. Which ordered pairs could be points on a line that is perpendicular to this line? Check all that apply. a. (-2,0) and (2,5) b. (-4,5) and (4,-5) c. (-3,4) and (2,0) d. (1,-1) and (6,-5) e. (2,-1) and (10,9)

QUESTION POSTED AT 19/02/2020 - 01:33 PM

Answered by admin AT 19/02/2020 - 01:33 PM

we know that

if two lines are perpendicular

then the product of their slopes is equal to minus one

so

m1*m2=-1

in this problem we have

m1=-\frac{4}{5}

the value of m2 must be equal to

m2=-\frac{1}{m1} =-\frac{1}{(-4/5)}=\frac{5}{4}

we know that

The formula to calculate the slope between two points is equal to

m=\frac{(y2-y1)}{(x2-x1)}

Find the slopes of each of ordered pairs and compare with m2

case a) (-2,0)\ and\ (2,5)

Substitute in the formula

m=\frac{(5-0)}{(2+2)}

m=\frac{(5)}{(4)}

The slope is equal to m2

so

The ordered pair case a)  could be points on a line that is perpendicular to the given  line

case b) (-4,5)\ and\ (4,-5)

Substitute in the formula

m=\frac{(-5-5)}{(4+4)}

m=\frac{(-10)}{(8)}

m=-\frac{5}{4}

The slope is not equal to m2

so

The ordered pair case b)  could not be points on a line that is perpendicular to the given  line

case c) (-3,4)\ and\ (2,0)

Substitute in the formula

m=\frac{(0-4)}{(2+3)}

m=\frac{(-4)}{(5)}

The slope is not equal to m2

so

The ordered pair case c)  could not be points on a line that is perpendicular to the given  line

case d) (1,-1)\ and\ (6,-5)

Substitute in the formula

m=\frac{(-5+1)}{(6-1)}

m=\frac{(-4)}{(5)}

The slope is not equal to m2

so

The ordered pair case d)  could not be points on a line that is perpendicular to the given  line

case e) (2,-1)\ and\ (10,9)

Substitute in the formula

m=\frac{(9+1)}{(10-2)}

m=\frac{(10)}{(8)}

m=\frac{5}{4}

The slope is equal to m2

so

The ordered pair case e)  could be points on a line that is perpendicular to the given  line

therefore

the answer is

(-2,0)\ and\ (2,5)\\(2,-1)\ and\ (10,9)

Post your answer

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ANSWERED AT 28/03/2020 - 12:59 PM


QUESTION POSTED AT 28/03/2020 - 12:59 PM

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QUESTION POSTED AT 28/03/2020 - 12:48 PM

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ANSWERED AT 28/03/2020 - 12:48 PM


QUESTION POSTED AT 28/03/2020 - 12:48 PM

A bag of coins contains 2 quarters, 5 dimes, 3 nickels, and 4 pennies. If 2 coins are randomly chosen from the bag, one after the other, and not replaced, and if the total value of the chosen coins is 26 cents, what is the probability that a third coin randomly chosen from the bag will be a penny?

Answer:

B

Step-by-step explanation:

The 2 coins that have a combined value of 26 cents are a quarter and a penny. That means that 1 quarter and 1 penny must have already been removed from the bag. For this reason, the bag now contains 1 quarter, 5 dimes, 3 nickels, and 3 pennies. Therefore, the probability that a third coin randomly chosen from the bag will be a penny is

3

1 + 5 +3 + 3

=

3

12

=

1

4

.

ANSWERED AT 28/03/2020 - 12:47 PM


QUESTION POSTED AT 28/03/2020 - 12:47 PM

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ANSWERED AT 28/03/2020 - 12:47 PM


QUESTION POSTED AT 28/03/2020 - 12:47 PM

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ANSWERED AT 28/03/2020 - 12:42 PM


QUESTION POSTED AT 28/03/2020 - 12:42 PM

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ANSWERED AT 28/03/2020 - 12:41 PM


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ANSWERED AT 28/03/2020 - 12:24 PM


QUESTION POSTED AT 28/03/2020 - 12:24 PM

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ANSWERED AT 28/03/2020 - 12:23 PM


QUESTION POSTED AT 28/03/2020 - 12:23 PM