# Solve -(-4)+(-2)-(-3)

QUESTION POSTED AT 14/02/2020 - 03:47 PM

QUESTION POSTED AT 14/02/2020 - 03:47 PM

-(-4) + (-2) - (-3) =

4 - 2 + 3 = 5

4 - 2 + 3 = 5

Raising to a negative power just makes the base value into a fraction

For example, x^-1 turns into (1/x^1)

This means that your equation goes from

7^-1+9^-1 to (1/7)+(1/9)

1/7+1/9 simplifies to 16/63 after all of the common denominator stuff

So, in short 7^-1+9^-1 = 16/63

For example, x^-1 turns into (1/x^1)

This means that your equation goes from

7^-1+9^-1 to (1/7)+(1/9)

1/7+1/9 simplifies to 16/63 after all of the common denominator stuff

So, in short 7^-1+9^-1 = 16/63

ANSWERED AT 28/02/2020 - 07:26 AM

QUESTION POSTED AT 28/02/2020 - 07:26 AM

You would typically be given two equations to solve for two unknowns with matrices.

ANSWERED AT 28/02/2020 - 07:24 AM

QUESTION POSTED AT 28/02/2020 - 07:24 AM

3x-8y=-35

- First thing you need move the 3x to the right hand like this one

-8y=-3x-35 ( positive move to another side change to negative )

And then you need to move -8 to the right hand to !

y=-3/-8 -35/-8 so you need to change the negative to positive y=3/8 + 35/8 ( 3/8 mean 3 over 8 )

The answer is y= 3/8 + 35/8

- First thing you need move the 3x to the right hand like this one

-8y=-3x-35 ( positive move to another side change to negative )

And then you need to move -8 to the right hand to !

y=-3/-8 -35/-8 so you need to change the negative to positive y=3/8 + 35/8 ( 3/8 mean 3 over 8 )

The answer is y= 3/8 + 35/8

ANSWERED AT 28/02/2020 - 07:24 AM

QUESTION POSTED AT 28/02/2020 - 07:24 AM

I think that it either c or that the sines cannot be used.

ANSWERED AT 28/02/2020 - 07:23 AM

QUESTION POSTED AT 28/02/2020 - 07:23 AM

So because there is a graph we can pretty easily find the solution, lucky us!

So the solution is where the two paths cross or intersect.

Going off of (x,y) so the x is 3 and the y is -5

so the solution is (3,-5)

So the solution is where the two paths cross or intersect.

Going off of (x,y) so the x is 3 and the y is -5

so the solution is (3,-5)

ANSWERED AT 28/02/2020 - 07:22 AM

QUESTION POSTED AT 28/02/2020 - 07:22 AM

Raise each side to the 3rd power (^3) making the equation 2x-5=125,

Then, add 5 to both sides, making the equation 2x=130

Lastly, we divide by 2, making x=65

If we substitute 65 for x, the equation is still true

3✓(2(65)-5)=5

3✓(130-5)=5

3✓(125)=5

5=5

so, X=65

Then, add 5 to both sides, making the equation 2x=130

Lastly, we divide by 2, making x=65

If we substitute 65 for x, the equation is still true

3✓(2(65)-5)=5

3✓(130-5)=5

3✓(125)=5

5=5

so, X=65

ANSWERED AT 28/02/2020 - 07:22 AM

QUESTION POSTED AT 28/02/2020 - 07:22 AM

For the last missing box, I'd put 72.

ANSWERED AT 28/02/2020 - 07:12 AM

QUESTION POSTED AT 28/02/2020 - 07:12 AM

Shaun made her first error at step 3 cause she was suppose to 2.8 from 25 and she should have gotten 22.2 instead of -2.8

ANSWERED AT 28/02/2020 - 07:11 AM

QUESTION POSTED AT 28/02/2020 - 07:11 AM

I did the problem and I can assure you that the answer is 21

ANSWERED AT 28/02/2020 - 07:07 AM

QUESTION POSTED AT 28/02/2020 - 07:07 AM

4x(x-4)=0

4x=0 or x-4=0

x=0 or x=4

4x=0 or x-4=0

x=0 or x=4

ANSWERED AT 28/02/2020 - 07:06 AM

QUESTION POSTED AT 28/02/2020 - 07:06 AM

To find how many times an average person's heart beats you will need to divide 103,680 and 60. This is because in 1 minute there is 60 seconds. When you divide this you get 1,728. So the heart beats 1,728 times per minute. For the equation, write 103,680 then division sign, then write 60 then put a equal sign, then write 1,728!

ANSWERED AT 28/02/2020 - 07:06 AM

QUESTION POSTED AT 28/02/2020 - 07:06 AM

G^2+2=0,

g^2=-2

g= sqrt-2, not possible.

3g+1=0

3g=-1

g=-1/3

9 cannot be equal to zero for the last one.

g^2=-2

g= sqrt-2, not possible.

3g+1=0

3g=-1

g=-1/3

9 cannot be equal to zero for the last one.

ANSWERED AT 28/02/2020 - 07:04 AM

QUESTION POSTED AT 28/02/2020 - 07:04 AM

Https://us-static.z-dn.net/files/db9/061bca8d599fe9b43e437d043078083e.jpeg

ANSWERED AT 28/02/2020 - 07:00 AM

QUESTION POSTED AT 28/02/2020 - 07:00 AM

S is given as 58 degrees.

There are 180 degrees in a triangle. Using this you know that S + T + TUS = 180

T is given as 5x + 10

TUS can be defined as TUS + AUT = 180, or TUS = 180 - AUT

AUT is given as 11x + 2

Plug everything into the first equation to give you 58 + (5x + 10) + (180 - (11x + 2)) = 180

Solve for x, and be careful with the negative in front of (11x+2)

58 + 10 + 180 - 2 + 5x - 11x = 180

-6x = -66

x = 11

Plug x back into the equations for AUT and T to get your final answers.

AUT = 11(11) + 2 = 123 degrees

S = 58 degrees

T = 5(11) + 10 = 65 degrees

TUS = 180 - AUT = 180 - 123 = 57 degrees

You can check your answer by making sure

S + T + TUS = 180, which it does.

There are 180 degrees in a triangle. Using this you know that S + T + TUS = 180

T is given as 5x + 10

TUS can be defined as TUS + AUT = 180, or TUS = 180 - AUT

AUT is given as 11x + 2

Plug everything into the first equation to give you 58 + (5x + 10) + (180 - (11x + 2)) = 180

Solve for x, and be careful with the negative in front of (11x+2)

58 + 10 + 180 - 2 + 5x - 11x = 180

-6x = -66

x = 11

Plug x back into the equations for AUT and T to get your final answers.

AUT = 11(11) + 2 = 123 degrees

S = 58 degrees

T = 5(11) + 10 = 65 degrees

TUS = 180 - AUT = 180 - 123 = 57 degrees

You can check your answer by making sure

S + T + TUS = 180, which it does.

ANSWERED AT 28/02/2020 - 07:00 AM

QUESTION POSTED AT 28/02/2020 - 07:00 AM

You create a model or use the numbers. Like this: 2×3=6 then, 3×4=12 and you have the fraction 6/12

ANSWERED AT 28/02/2020 - 06:54 AM

QUESTION POSTED AT 28/02/2020 - 06:54 AM

Ella has 12 and Maria has 7. Ella can make three while Maria can make 8. I will do a side by side count for you.

12 + 3=15

7 + 8=15

In one more day Ella and Maria will have made the same amount of blankets.

12 + 3=15

7 + 8=15

In one more day Ella and Maria will have made the same amount of blankets.

ANSWERED AT 28/02/2020 - 06:50 AM

QUESTION POSTED AT 28/02/2020 - 06:50 AM

3. > x. 16. 5. -. ≥.

ANSWERED AT 28/02/2020 - 06:49 AM

QUESTION POSTED AT 28/02/2020 - 06:49 AM

This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5

ANSWERED AT 28/02/2020 - 06:46 AM

QUESTION POSTED AT 28/02/2020 - 06:46 AM

X = -1.949844

81 2(-1.949844)³ + (-1.949844)² = 0

27 6(-1.949844) - 3 = 0

0 = 0

81 2(-1.949844)³ + (-1.949844)² = 0

27 6(-1.949844) - 3 = 0

0 = 0

ANSWERED AT 28/02/2020 - 06:44 AM

QUESTION POSTED AT 28/02/2020 - 06:44 AM

ANSWERED AT 28/02/2020 - 06:38 AM

QUESTION POSTED AT 28/02/2020 - 06:38 AM

Find the area of the CD. (I used P for pi, too lazy @[email protected])

A=Pr² - Pr²

radius of the small hole in the middle, 0.75cm

radius of the CD, 6cm

A=3.14*6²-3.14*0.75²

A=111.27375cm²

**The Approximate area of the CD is 111.27cm²**

A=Pr² - Pr²

radius of the small hole in the middle, 0.75cm

radius of the CD, 6cm

A=3.14*6²-3.14*0.75²

A=111.27375cm²

ANSWERED AT 28/02/2020 - 06:29 AM

QUESTION POSTED AT 28/02/2020 - 06:29 AM

First you do a equation which is 6 divided by 4 which gives you 5 remainder 1 so 1/5 or 1.5

ANSWERED AT 28/02/2020 - 06:18 AM

QUESTION POSTED AT 28/02/2020 - 06:18 AM

45: 100% - 17% = **83%**

47: 44/2 = 22

22 - 1 = 21

**See attached file**

47: 44/2 = 22

22 - 1 = 21

ANSWERED AT 28/02/2020 - 06:16 AM

QUESTION POSTED AT 28/02/2020 - 06:16 AM

On a coordinate plane, any movement up and down is on the y-axis. So if your parallelogram is moving down 2.5 units, then the y-values of each vertice will go down by 2.5:

A(-2, -8), B(-4, -8), C(-3, -4.5), D(-1, -4.5)

A(-2, -8), B(-4, -8), C(-3, -4.5), D(-1, -4.5)

ANSWERED AT 28/02/2020 - 06:15 AM

QUESTION POSTED AT 28/02/2020 - 06:15 AM

So.. if you take a peek at the picture below

the trunk is really just a half-cylinder on top of a square, with a depth of 2 meters

what's the volume? well, easy enough, take the volume of the cylinder, then half it

take the volume of the rectangular prism, and then add them both

now.. for the surface area...

now.. for the surface area of the prism... well

is really just 6 rectangles stacked up to each other at the edges

so... get the area of the lateral rectangles, and the one at the bottom, skip the rectangle atop, because is the one overlapping the cylinder, and is not outside, and thus is not surface area then

for the lateral ones, you have a front of 1x1, a back of 1x1 and a left of 1x2 and a right of 1x2, and then the one at the bottom, which is a 1x2

then add both surface areas, and that's the surface area of the trunk

the trunk is really just a half-cylinder on top of a square, with a depth of 2 meters

what's the volume? well, easy enough, take the volume of the cylinder, then half it

take the volume of the rectangular prism, and then add them both

now.. for the surface area...

now.. for the surface area of the prism... well

is really just 6 rectangles stacked up to each other at the edges

so... get the area of the lateral rectangles, and the one at the bottom, skip the rectangle atop, because is the one overlapping the cylinder, and is not outside, and thus is not surface area then

for the lateral ones, you have a front of 1x1, a back of 1x1 and a left of 1x2 and a right of 1x2, and then the one at the bottom, which is a 1x2

then add both surface areas, and that's the surface area of the trunk

ANSWERED AT 28/02/2020 - 06:11 AM

QUESTION POSTED AT 28/02/2020 - 06:11 AM

Z=180-84-50

x=180-84-63

y=180-33-13

z=46

x=33

y=134

x=180-84-63

y=180-33-13

z=46

x=33

y=134

ANSWERED AT 28/02/2020 - 06:07 AM

QUESTION POSTED AT 28/02/2020 - 06:07 AM

A.

domain is th enumbers you can use

remember you cannot take square root of a negative

also you cannot divide by 0

domain is all real numbers except those that result in a square root of a negative or division by 0

domain is how far left or right the graph goes

range is the output from inputing the domain, it is how far up and down the graph goes

a. domain is

hmm, squaerr root

see under parenthasees

x+1

so x≥0 is the domain

domain is x≥0

so then the range is from 0 to infinity or y≥0

b. replace f(x) with y and switch x and y and solve for y

y=√(x+1)

x=√(y+1)

square

x²=y+1

x²-1=y

f⁻¹(x)=x²-1

domain is all real numbers

range, this is a parabola, when it gets to x=0, y=-1 that is minimum

range is y≥-1 or from -1 to infinity

basicaly show that f(f⁻¹(x))=x=f⁻¹(f(x))

so if you did that

f(f⁻¹(x))=√(x²-1+1)

f(f⁻¹(x))=√(x²)

f(f⁻¹(x))=x

reverse

f⁻¹(f(x))=(√(x+1))²-1

f⁻¹(f(x))=x+1-1

f⁻¹(f(x))=x

d.

√(x+1)=x²-1

squaer both sides

x+1=x⁴-2x²+1

minus x both sides and minus 1

0=x⁴-2x²-x

factor

0=(x)(x+1)(x²-x-1)

x=0 and x=-1 and 0.5+0.5√5 and 0.5-0.5√5

test them

wait, the last one isn't in the domain

if we did x=0, then we get 1=-1, false

the soltions are x=-1 and

e. do ths yourself

try demos graphing calculator

domain is th enumbers you can use

remember you cannot take square root of a negative

also you cannot divide by 0

domain is all real numbers except those that result in a square root of a negative or division by 0

domain is how far left or right the graph goes

range is the output from inputing the domain, it is how far up and down the graph goes

a. domain is

hmm, squaerr root

see under parenthasees

x+1

so x≥0 is the domain

domain is x≥0

so then the range is from 0 to infinity or y≥0

b. replace f(x) with y and switch x and y and solve for y

y=√(x+1)

x=√(y+1)

square

x²=y+1

x²-1=y

f⁻¹(x)=x²-1

domain is all real numbers

range, this is a parabola, when it gets to x=0, y=-1 that is minimum

range is y≥-1 or from -1 to infinity

basicaly show that f(f⁻¹(x))=x=f⁻¹(f(x))

so if you did that

f(f⁻¹(x))=√(x²-1+1)

f(f⁻¹(x))=√(x²)

f(f⁻¹(x))=x

reverse

f⁻¹(f(x))=(√(x+1))²-1

f⁻¹(f(x))=x+1-1

f⁻¹(f(x))=x

d.

√(x+1)=x²-1

squaer both sides

x+1=x⁴-2x²+1

minus x both sides and minus 1

0=x⁴-2x²-x

factor

0=(x)(x+1)(x²-x-1)

x=0 and x=-1 and 0.5+0.5√5 and 0.5-0.5√5

test them

wait, the last one isn't in the domain

if we did x=0, then we get 1=-1, false

the soltions are x=-1 and

e. do ths yourself

try demos graphing calculator

ANSWERED AT 28/02/2020 - 06:05 AM

QUESTION POSTED AT 28/02/2020 - 06:05 AM

Let's solve the equation, c^2 - c - 90 = 0 step by step

Step 1: Factor left side of the equation

(c + 9)(c - 10) = 0

Step 2: Set factors equal to zero

c + 9 = 0, or c - 10 = 0

c = -9, or c = 10

As you can see the answer is c = -9, or c = 10

Hope this helps! - Alyssa :)

Step 1: Factor left side of the equation

(c + 9)(c - 10) = 0

Step 2: Set factors equal to zero

c + 9 = 0, or c - 10 = 0

c = -9, or c = 10

As you can see the answer is c = -9, or c = 10

Hope this helps! - Alyssa :)

ANSWERED AT 28/02/2020 - 06:02 AM

QUESTION POSTED AT 28/02/2020 - 06:02 AM

Well, to find what that middle point is on XZ

once you found that, then use it in the distance equation

once you found that, then use it in the distance equation

ANSWERED AT 28/02/2020 - 06:02 AM

QUESTION POSTED AT 28/02/2020 - 06:02 AM

Solve what.............

ANSWERED AT 28/02/2020 - 06:02 AM

QUESTION POSTED AT 28/02/2020 - 06:02 AM