# What is the range of the data in this stem-and-leaf plot? 2 14 19 32.5

QUESTION POSTED AT 26/03/2020 - 02:33 PM

QUESTION POSTED AT 26/03/2020 - 02:33 PM

**Answer:**

19

**Step-by-step explanation:**

Stem and Leaf Plots

**It is a special table where each data value is split into a stem (the first digit or digits) and a leaf (usually the last digit).**

So, in the given plot

**the first stem 2 has leafs = 6,7,7**

**So, the numbers will be 26,27,27**

So, in this way we can write the stem leaf plot data in normal data form

Now to calculate range

**Range = Highest number - lowest number**

**The first stem 2 and its first leaf 6 . So,number = 26 is the lowest number **

**The third stem 4 and its last leaf 5 . So, number = 45 is the highest number **

**Thus Range = 45-26=19**

**Hence the range of data is 19**

First, you need to put the numbers in order

50, 50, 70,**80, 90**, 100, 100, 100

Mean: 80

Median: 85 (80+90=**170**/2= **85**)

Range: 50

Mode: 100, appeared 3 times

Largest Number: 100

Smallest Number:50

Sum of all numbers: 640

Number Count: 8

So, your answer is**A. M****edian: 85 and Mode: 100 **

Hope this helps!!

50, 50, 70,

Mean: 80

Median: 85 (80+90=

Range: 50

Mode: 100, appeared 3 times

Largest Number: 100

Smallest Number:50

Sum of all numbers: 640

Number Count: 8

So, your answer is

ANSWERED AT 28/03/2020 - 12:58 PM

QUESTION POSTED AT 28/03/2020 - 12:58 PM

It helps you determine the characteristics of the plot/graph. I am not sure so it is your choose.

ANSWERED AT 28/03/2020 - 12:54 PM

QUESTION POSTED AT 28/03/2020 - 12:54 PM

**Answer:**

Mode does not exist

**Step-by-step explanation:**

**Mode** of any data set is the data with the highest frequency(i.e. that term which is repeated most in the data set)

Here, credit scores in Will's office are:

634 667 644 892 627 821 857 703 654

No term is repeated hence, the mode does not exist

ANSWERED AT 28/03/2020 - 12:48 PM

QUESTION POSTED AT 28/03/2020 - 12:48 PM

**Answer:**

The median of Group 2 is greater than the median of Group 1.

**Step-by-step explanation:**

ANSWERED AT 28/03/2020 - 12:48 PM

QUESTION POSTED AT 28/03/2020 - 12:48 PM

In a right triangle, the hypotenuse is always the longest side. Plus, the hypotenuse squared has to equal the sum of the squares of the other 2 sides. For the first "triangle" above: does ? Let's check. 196 = 25 + 16 so does 196 = 41? Obviously not. So that is not a right triangle. Let's check the second one the same way. Does ? 25 = 9 + 16. Does 25 = 25? Of course it does! So 1 is not a right triangle, but 2 is!

ANSWERED AT 28/03/2020 - 12:48 PM

QUESTION POSTED AT 28/03/2020 - 12:48 PM

**Answer:**

correct option is:

613

**Step-by-step explanation:**

Out of 150 people(50 people day 1, 50 people day 2 and 50 people day 3)

40 people prefer vanilla (13 of day 1,12 of day 2 and 15 of day 3)

That means, out of 150 : 40 prefer vanilla

out of 2300 : prefer vanilla

≈ 613

**Hence, the correct option is:**

** 613**

ANSWERED AT 28/03/2020 - 12:47 PM

QUESTION POSTED AT 28/03/2020 - 12:47 PM

There are ten (10) total dinners included in this histogram.

The most popular price range is fifteen to thirty dollars and thirty to forty-five dollars.

The most popular price range is fifteen to thirty dollars and thirty to forty-five dollars.

ANSWERED AT 28/03/2020 - 12:45 PM

QUESTION POSTED AT 28/03/2020 - 12:45 PM

**The length of the longest metal rod that can be sent is 12 inches.**

As given, the only boxes available for shipping are 7-inch cubes. As Jorge needs to ship a thin metal rod to a metalworking shop, he will put the rods diagonally or space diagonally in the box.

The space diagonal of a cube can be found by the formula :

=

Here, x is 7 inches.

So, Diagonal is =

= inches.

Rounding this to nearest whole number we get 12.

**So, the length of the longest metal rod that can be sent is 12 inches.**

ANSWERED AT 28/03/2020 - 12:44 PM

QUESTION POSTED AT 28/03/2020 - 12:44 PM

The interquartile range answer is 8.5

ANSWERED AT 28/03/2020 - 12:40 PM

QUESTION POSTED AT 28/03/2020 - 12:40 PM

**Answer:**

Option A. 6.25

**Step-by-step explanation:**

The data shows the number of grams of fat found in different health bars is

11, 11.5, 10.5, 17, 14.5, 14.5, 18, 17, 19

Now we will arrange the data in ascending order

10.5, 11, 11.5, 14.5,** 14.5**, 17, 17, 18, 19

Middle of the numbers is 14.5 which is median of the data.

We know IQR = Median of first quartile - median of second quartile

Median of first quartile =

And median of second quartile =

Now IQR = 17.5 - 11.25 = 6.25

Therefore **Option A 6.25** is the correct option.

ANSWERED AT 28/03/2020 - 12:38 PM

QUESTION POSTED AT 28/03/2020 - 12:38 PM

Choice A. Work done below:

4x-1=5x-8 ( Set the opposite sides equal to each other).

4x-5x-1=-8 (Subtract 5x on both sides)

-x-1=-8 (Combine like terms)

-x=-8+1( Add 1 on both sides)

-x=-7 (Now since you have a negative sign on both sides you can cancel them)

x=7 ( Making that as your answer!!)

4x-1=5x-8 ( Set the opposite sides equal to each other).

4x-5x-1=-8 (Subtract 5x on both sides)

-x-1=-8 (Combine like terms)

-x=-8+1( Add 1 on both sides)

-x=-7 (Now since you have a negative sign on both sides you can cancel them)

x=7 ( Making that as your answer!!)

ANSWERED AT 28/03/2020 - 12:33 PM

QUESTION POSTED AT 28/03/2020 - 12:33 PM

2 were older than 40 and the rest were younger then 20

ANSWERED AT 28/03/2020 - 12:25 PM

QUESTION POSTED AT 28/03/2020 - 12:25 PM

The answer is A again

ANSWERED AT 28/03/2020 - 12:25 PM

QUESTION POSTED AT 28/03/2020 - 12:25 PM

First quartile is 13

Third quartile is 17.75

Take 17.75 - 13 = 4.75

The IQR is 4.75

Third quartile is 17.75

Take 17.75 - 13 = 4.75

The IQR is 4.75

ANSWERED AT 28/03/2020 - 12:24 PM

QUESTION POSTED AT 28/03/2020 - 12:24 PM

a.11 is your best answer

ANSWERED AT 28/03/2020 - 12:21 PM

QUESTION POSTED AT 28/03/2020 - 12:21 PM

If they give you what one variable is, you can plug it into the equation and use algebra to solve it. So:

1)2x=4 -> 4/2 = 2 so x=2

2) y=0

3) x=3

4) 2y + (3*3y) = -15

11y=-15

y = -15/11

5) 4x + 7x + 63 = 19

11x = -44

x = -4

1)2x=4 -> 4/2 = 2 so x=2

2) y=0

3) x=3

4) 2y + (3*3y) = -15

11y=-15

y = -15/11

5) 4x + 7x + 63 = 19

11x = -44

x = -4

ANSWERED AT 28/03/2020 - 12:21 PM

QUESTION POSTED AT 28/03/2020 - 12:21 PM

To find the mean of a given data set, add up all the values then divide by how many numbers there are.

11 + 16 + 22 + 28 + 29 + 30 + 31 + 34 + 37 + 38 + 43 + 49 + 56 + 78 + 99 =**601**

601 / 15 =**40.06666**

**Round the answer to ****40.1**** > Choice C is your answer**

11 + 16 + 22 + 28 + 29 + 30 + 31 + 34 + 37 + 38 + 43 + 49 + 56 + 78 + 99 =

601 / 15 =

ANSWERED AT 28/03/2020 - 12:19 PM

QUESTION POSTED AT 28/03/2020 - 12:19 PM

Amplitude: the height of the graph from the peak to the axis. On the unit circle it would be the radius (max and min values) at 0, pi/2, 2pi

Period: the length of one full cycle of the cos graph. On the unit circle it is the circumference. The distance around a circle with radius = 1.

Domain: the x value or the values on the horizontal axis. On the unit circle these would be the radian measures around the unit circle such as pi/6, pi/4,

pi/3, pi/2.

Range: the y value or the values on the vertical axis. On the unit circle it would be the cosine value for each radian measure. Such as cos pi/4 = (sqrt2)/2, cos pi/3= 1/2.

X-intercepts: the points where the graph crosses the horizontal axis. On the unit circle these are the cosine values when theta is at the vertical points of the unit circle, pi/2 and 3pi/2.

Period: the length of one full cycle of the cos graph. On the unit circle it is the circumference. The distance around a circle with radius = 1.

Domain: the x value or the values on the horizontal axis. On the unit circle these would be the radian measures around the unit circle such as pi/6, pi/4,

pi/3, pi/2.

Range: the y value or the values on the vertical axis. On the unit circle it would be the cosine value for each radian measure. Such as cos pi/4 = (sqrt2)/2, cos pi/3= 1/2.

X-intercepts: the points where the graph crosses the horizontal axis. On the unit circle these are the cosine values when theta is at the vertical points of the unit circle, pi/2 and 3pi/2.

ANSWERED AT 28/03/2020 - 12:19 PM

QUESTION POSTED AT 28/03/2020 - 12:19 PM

The answer is A because 42 is in the middle.

ANSWERED AT 28/03/2020 - 12:17 PM

QUESTION POSTED AT 28/03/2020 - 12:17 PM

The answer would be B 23

ANSWERED AT 28/03/2020 - 12:11 PM

QUESTION POSTED AT 28/03/2020 - 12:11 PM

**Answer: Option B. the weather is generally sunnier in City 2. **

**Step-by-step explanation: if you look at the line plots city 2 has more warm weather than city 1 does and if you also look city 2 does have a least one day with 80 degrees where as city 1 does not even have one day with 80 degrees. **

ANSWERED AT 28/03/2020 - 12:10 PM

QUESTION POSTED AT 28/03/2020 - 12:10 PM

We need to locate the median of the set given. So, it's important for us to arrange the data in increasing order first. Hence we have

10.5 11 11.5 14.5 14.5 17 17 18 19

Now that we have the value of the median for the entire set, we now separate the group into a group below and above the median as shown below.

(10.5 11 11.5 14.5) 14.5 (17 17 18 19)

Now, let's find the median for the subgroup. For the lower boundary, the media is (11 + 11.5)/2 = 11.25. As for the upper boundary, we have (17 + 18)/2 = 17.5.

The interquartile range (IQR) is the difference between the two medians of the lower and upper boundary. Hence, the IQR = 17.5 - 11.25 = 6.25.

**Answer: 6.25**

10.5 11 11.5 14.5 14.5 17 17 18 19

Now that we have the value of the median for the entire set, we now separate the group into a group below and above the median as shown below.

(10.5 11 11.5 14.5) 14.5 (17 17 18 19)

Now, let's find the median for the subgroup. For the lower boundary, the media is (11 + 11.5)/2 = 11.25. As for the upper boundary, we have (17 + 18)/2 = 17.5.

The interquartile range (IQR) is the difference between the two medians of the lower and upper boundary. Hence, the IQR = 17.5 - 11.25 = 6.25.

ANSWERED AT 28/03/2020 - 12:05 PM

QUESTION POSTED AT 28/03/2020 - 12:05 PM

the answer is B

because 54x 3= 162 x3 = 486x3= 1458x3=4,374x3=13,122x3=39,366x3=118,098x3=354,294

ANSWERED AT 28/03/2020 - 12:05 PM

QUESTION POSTED AT 28/03/2020 - 12:05 PM

Y=31/36 calculating by the method subtraction and then cross multiplying

ANSWERED AT 28/03/2020 - 12:02 PM

QUESTION POSTED AT 28/03/2020 - 12:02 PM

Twenty-five percent of his friends have 13 or more baseball cards.

ANSWERED AT 28/03/2020 - 12:01 PM

QUESTION POSTED AT 28/03/2020 - 12:01 PM

Should be the second one dear

ANSWERED AT 28/03/2020 - 11:58 AM

QUESTION POSTED AT 28/03/2020 - 11:58 AM

**Answer:**

c.$21,000

**Step-by-step explanation:**

In order to solve this you just have to add up assets and liabilities, assets are the money or worth they own, and liabilities are the things htey owe, so assets are:

Liquid: $10,000

Investments: $34,000

Use Assets: $150,000

Total assets: $194,000

Liabilities:108,000+7,000: 115,000

Net worth: $194,000-$115,000= $79,000

So in order to have a net worth of $100,000 they will need to increase their assests in $21,000.

ANSWERED AT 28/03/2020 - 11:57 AM

QUESTION POSTED AT 28/03/2020 - 11:57 AM

The triangle in the image below shows the **RED** line and 2 **GREEN** lines.

*The RED line is the Hypotenuse MN*

*The two GREEN lines connect to form a right triangle to complete this triangle.*

**Point (5, -2)** is the point on the fourth quadrant that is the **third vertex of the right triangle.**

**ANSWER: (5,-2) is the 3rd vertex of the right triangle (graph shown)**

ANSWERED AT 28/03/2020 - 11:52 AM

QUESTION POSTED AT 28/03/2020 - 11:52 AM

C....to be a function x can only be one value

ANSWERED AT 28/03/2020 - 11:52 AM

QUESTION POSTED AT 28/03/2020 - 11:52 AM

#2 A
number line ranging from negative 2 to positive 2, with increments of 1
fourth. The area between zero and negative 1 fourth is in brackets with
negative 1 fourth written above it. The area between negative 1 fourth
and negative 3 fourths is in brackets, with negative 1 half written
above it. is your answer

ANSWERED AT 28/03/2020 - 11:45 AM

QUESTION POSTED AT 28/03/2020 - 11:45 AM