# If x-y=8,find the value of y when x=3

QUESTION POSTED AT 20/02/2020 - 11:18 PM

QUESTION POSTED AT 20/02/2020 - 11:18 PM

3-y=8

-y=8-3

y=-5

so just try to re arrange the equation to find the value for the variable

-y=8-3

y=-5

so just try to re arrange the equation to find the value for the variable

The best answer is B

ANSWERED AT 28/03/2020 - 12:58 PM

QUESTION POSTED AT 28/03/2020 - 12:58 PM

The answer to this is letter A)

ANSWERED AT 28/03/2020 - 12:53 PM

QUESTION POSTED AT 28/03/2020 - 12:53 PM

ANSWERED AT 28/03/2020 - 12:32 PM

QUESTION POSTED AT 28/03/2020 - 12:32 PM

I think the answer is C

ANSWERED AT 28/03/2020 - 12:25 PM

QUESTION POSTED AT 28/03/2020 - 12:25 PM

If they give you what one variable is, you can plug it into the equation and use algebra to solve it. So:

1)2x=4 -> 4/2 = 2 so x=2

2) y=0

3) x=3

4) 2y + (3*3y) = -15

11y=-15

y = -15/11

5) 4x + 7x + 63 = 19

11x = -44

x = -4

1)2x=4 -> 4/2 = 2 so x=2

2) y=0

3) x=3

4) 2y + (3*3y) = -15

11y=-15

y = -15/11

5) 4x + 7x + 63 = 19

11x = -44

x = -4

ANSWERED AT 28/03/2020 - 12:21 PM

QUESTION POSTED AT 28/03/2020 - 12:21 PM

Therefore, x/(x-2) = 3. so, x = 3

ANSWERED AT 28/03/2020 - 12:16 PM

QUESTION POSTED AT 28/03/2020 - 12:16 PM

**Answer:**

**Step-by-step explanation:**

ANSWERED AT 28/03/2020 - 12:06 PM

QUESTION POSTED AT 28/03/2020 - 12:06 PM

1,3 and 5 on ed.genuity

ANSWERED AT 28/03/2020 - 12:02 PM

QUESTION POSTED AT 28/03/2020 - 12:02 PM

X<-3 would be the answer

ANSWERED AT 28/03/2020 - 11:59 AM

QUESTION POSTED AT 28/03/2020 - 11:59 AM

10 and so what is the

ANSWERED AT 28/03/2020 - 11:59 AM

QUESTION POSTED AT 28/03/2020 - 11:59 AM

Should be the second one dear

ANSWERED AT 28/03/2020 - 11:58 AM

QUESTION POSTED AT 28/03/2020 - 11:58 AM

C....to be a function x can only be one value

ANSWERED AT 28/03/2020 - 11:52 AM

QUESTION POSTED AT 28/03/2020 - 11:52 AM

The correct answer is B.

ANSWERED AT 28/03/2020 - 11:46 AM

QUESTION POSTED AT 28/03/2020 - 11:46 AM

You start from in to out, so in the case of h (f (x)) we start by substituting f (x)

By substituting f (x) you get h (x-7)

Now substitute x-7 in x's in the function h (x)

2x+3 will be 2 (x-7)+3

Therefore, h (f (x)) is 2x-14+3 which is 2x-11

By substituting f (x) you get h (x-7)

Now substitute x-7 in x's in the function h (x)

2x+3 will be 2 (x-7)+3

Therefore, h (f (x)) is 2x-14+3 which is 2x-11

ANSWERED AT 28/03/2020 - 11:18 AM

QUESTION POSTED AT 28/03/2020 - 11:18 AM

The correct answer is 7

Hope this helped :)

Hope this helped :)

ANSWERED AT 28/03/2020 - 11:18 AM

QUESTION POSTED AT 28/03/2020 - 11:18 AM

3 (2x-4)-6 (x-3)

Distribute by multiplication 3 to both 2x and -4

And distribute by multiplication -6 to both x and -3

6x-12-6x+18

Add like terms

6

Distribute by multiplication 3 to both 2x and -4

And distribute by multiplication -6 to both x and -3

6x-12-6x+18

Add like terms

6

ANSWERED AT 28/03/2020 - 11:17 AM

QUESTION POSTED AT 28/03/2020 - 11:17 AM

so hmmm since it's implicit differentiation, you'd get a function in x,y terms so. hmm if we check the graph of that second derivative, it seems to be asymptotic at x = -1, meaning an inflection point, from the denominator equaling 0

and it has an x-intercept at the origin, x = 0, another inflection point

now, the graph of the second derivative, from x > 0, the value for "y" is positive all the way, with a horizontal asymptote at y = 0

meaning the original function f(x) is concave UP at x > 0

now, when -1 < x < 0, the value of "y" drops to the negatives, thus is concave DOWN at -1 < x < 0

and if we pass the asymptotic inflection point of x = -1, to the left

x < -1, the value of "y" is on the positives, thus concave UP on that region

ANSWERED AT 28/03/2020 - 11:01 AM

QUESTION POSTED AT 28/03/2020 - 11:01 AM

Domain A matches Range 2 because

40/2.5 = 16 , 45/ 2.5 = 18 and so on -all 5 work ou.

If you do the same calculations for B, C and D you'll get the correct answers

It looks like Domain B matches Range 1:- 52 / 2.5 = 20.8, 56/2.5 = 22.4

- I think I can leave you to finish this off .

40/2.5 = 16 , 45/ 2.5 = 18 and so on -all 5 work ou.

If you do the same calculations for B, C and D you'll get the correct answers

It looks like Domain B matches Range 1:- 52 / 2.5 = 20.8, 56/2.5 = 22.4

- I think I can leave you to finish this off .

ANSWERED AT 28/03/2020 - 11:00 AM

QUESTION POSTED AT 28/03/2020 - 11:00 AM

#3. Plugging the point (3,0) into any of the equations except the third one gives an invalid answer.

ANSWERED AT 28/03/2020 - 10:53 AM

QUESTION POSTED AT 28/03/2020 - 10:53 AM

Hmm... I think the answer is C) x = 5. Have a great day!!

ANSWERED AT 28/03/2020 - 10:49 AM

QUESTION POSTED AT 28/03/2020 - 10:49 AM

First, you would have to plug 3 into the equation

15-(3)/9-(3)

Then do the math

12/6

This can be simplified, since 12 and 6 are divisible by 6, which is their greatest common factor

2/1

**So the answer is D. 2**

Hope this helps!

15-(3)/9-(3)

Then do the math

12/6

This can be simplified, since 12 and 6 are divisible by 6, which is their greatest common factor

2/1

Hope this helps!

ANSWERED AT 28/03/2020 - 10:47 AM

QUESTION POSTED AT 28/03/2020 - 10:47 AM

C) his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

8*(x-4)=2*(x+2).

8*x-8*4=2*x+2*2;

8x-32=2x+4.

8x-32-2x=2x+4-2x;

6x-32=4.

6x-32+32=4+32;

6x=36.

=;

x=6.

ANSWERED AT 28/03/2020 - 10:40 AM

QUESTION POSTED AT 28/03/2020 - 10:40 AM

A reflection about the x axis and a reflection about the y axis

ANSWERED AT 28/03/2020 - 10:19 AM

QUESTION POSTED AT 28/03/2020 - 10:19 AM

this will be continued

ANSWERED AT 28/03/2020 - 10:18 AM

QUESTION POSTED AT 28/03/2020 - 10:18 AM

Its C (0,0) as the Graph indicated

ANSWERED AT 28/03/2020 - 10:15 AM

QUESTION POSTED AT 28/03/2020 - 10:15 AM

Let x = the width

it says, "The length of a rectangle is 4 less than 3 times the width." write that as:

L = 3x - 4

If the perimeter is 40, find the dimensions of the rectangle.

We know: 2L + 2W = 40

Substitute (3x-4) for L and x for W

2(3x-4) + 2x = 40

6x - 8 + 2x = 40; multiplied what's inside the brackets

6x + 2x = 40 + 8; do some basic alegbra to find x; (added 8 to both sides)

8x = 48

x = 48/8

x = 6 which is the width

It said that L = 3x - 4, therefore:

L = 3(6) - 4

L = 18 - 4

L = 14; is the length

Check our solutions in the perimeter:

2(14) + 2(6) =

28 + 12 = 40

it says, "The length of a rectangle is 4 less than 3 times the width." write that as:

L = 3x - 4

If the perimeter is 40, find the dimensions of the rectangle.

We know: 2L + 2W = 40

Substitute (3x-4) for L and x for W

2(3x-4) + 2x = 40

6x - 8 + 2x = 40; multiplied what's inside the brackets

6x + 2x = 40 + 8; do some basic alegbra to find x; (added 8 to both sides)

8x = 48

x = 48/8

x = 6 which is the width

It said that L = 3x - 4, therefore:

L = 3(6) - 4

L = 18 - 4

L = 14; is the length

Check our solutions in the perimeter:

2(14) + 2(6) =

28 + 12 = 40

ANSWERED AT 27/03/2020 - 01:06 PM

QUESTION POSTED AT 27/03/2020 - 01:06 PM

(12,24)

Hope it helps love.

-Joker7721

Hope it helps love.

-Joker7721

ANSWERED AT 27/03/2020 - 01:05 PM

QUESTION POSTED AT 27/03/2020 - 01:05 PM

At x = 0, y = 0 (x1,y1)

at x = 4, y = 16 (x2,y2)

slope = (y2 - y1)/(x2 - x1)

slope = (16 - 0)/(4 - 0)

slope = 16/4

slope = 4

at x = 4, y = 16 (x2,y2)

slope = (y2 - y1)/(x2 - x1)

slope = (16 - 0)/(4 - 0)

slope = 16/4

slope = 4

ANSWERED AT 27/03/2020 - 12:30 PM

QUESTION POSTED AT 27/03/2020 - 12:30 PM

**Answer:**

{3/2}x + 3

**Step-by-step explanation:**

Hope this helps

ANSWERED AT 27/03/2020 - 10:10 AM

QUESTION POSTED AT 27/03/2020 - 10:10 AM

X²/25 + y²/100 =1

4x²/100+ y²/100 =1

4x²+y²=100

y²=100- 4x²

If x=0, y²= 100, y = ±10

c{(0,-10),(0,10)}

If y=0, 4x²= 100, x²=25, x=±5

d {(-5,0),(5,0)}

4x²/100+ y²/100 =1

4x²+y²=100

y²=100- 4x²

If x=0, y²= 100, y = ±10

c{(0,-10),(0,10)}

If y=0, 4x²= 100, x²=25, x=±5

d {(-5,0),(5,0)}

ANSWERED AT 27/03/2020 - 10:05 AM

QUESTION POSTED AT 27/03/2020 - 10:05 AM