A Trapezoid has an area of 5 1/2 ft sq. If the trapezoid has a base that measures 2 3/5 ft and a height of 1 1/2 ft, what is the length of the other base?
QUESTION POSTED AT 16/04/2020 - 06:13 PM
Answered by admin AT 16/04/2020 - 06:13 PM
First of all, let us change all the mixed number into improper fraction:
5 1/2=11/2
2 3/5=13/5
1 1/2=3/2
Area of the trapezoid=
1/2(b1+b2)×h
11/2=1/2(13/5+b2)×3/2
Divided 3/2 or multiply 2/3 for both side
11/2×2/3=1/2(13/5+b2)×3/2×2/3
11/3=1/2(13/5+b2)
Multiply 2 for both side
11/3×2=1/2(13/5+b2)×2
22/3=13/5+b2
Subtract 13/5 for both side
b2= 4 11/15. As a result, the length of other base is 4 11/15 feet. Hope it help!
5 1/2=11/2
2 3/5=13/5
1 1/2=3/2
Area of the trapezoid=
1/2(b1+b2)×h
11/2=1/2(13/5+b2)×3/2
Divided 3/2 or multiply 2/3 for both side
11/2×2/3=1/2(13/5+b2)×3/2×2/3
11/3=1/2(13/5+b2)
Multiply 2 for both side
11/3×2=1/2(13/5+b2)×2
22/3=13/5+b2
Subtract 13/5 for both side
b2= 4 11/15. As a result, the length of other base is 4 11/15 feet. Hope it help!
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