# A Trapezoid has an area of 5 1/2 ft sq. If the trapezoid has a base that measures 2 3/5 ft and a height of 1 1/2 ft, what is the length of the other base?

QUESTION POSTED AT 16/04/2020 - 06:13 PM

QUESTION POSTED AT 16/04/2020 - 06:13 PM

First of all, let us change all the mixed number into improper fraction:

5 1/2=11/2

2 3/5=13/5

1 1/2=3/2

Area of the trapezoid=

1/2(b1+b2)×h

11/2=1/2(13/5+b2)×3/2

Divided 3/2 or multiply 2/3 for both side

11/2×2/3=1/2(13/5+b2)×3/2×2/3

11/3=1/2(13/5+b2)

Multiply 2 for both side

11/3×2=1/2(13/5+b2)×2

22/3=13/5+b2

Subtract 13/5 for both side

b2= 4 11/15. As a result, the length of other base is 4 11/15 feet. Hope it help!

5 1/2=11/2

2 3/5=13/5

1 1/2=3/2

Area of the trapezoid=

1/2(b1+b2)×h

11/2=1/2(13/5+b2)×3/2

Divided 3/2 or multiply 2/3 for both side

11/2×2/3=1/2(13/5+b2)×3/2×2/3

11/3=1/2(13/5+b2)

Multiply 2 for both side

11/3×2=1/2(13/5+b2)×2

22/3=13/5+b2

Subtract 13/5 for both side

b2= 4 11/15. As a result, the length of other base is 4 11/15 feet. Hope it help!

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