# Find the area of the shaded portion. Show all work for full credit.

QUESTION POSTED AT 16/04/2020 - 07:39 PM

QUESTION POSTED AT 16/04/2020 - 07:39 PM

Draw some lines and we get some special 30-60-90 triangless

se diagram

so using my math

remember that if the hyptonuse is 2x then angle oposite the 30 degree is x and angle oposit the 60 degree is x√3

so

we have a kite and know the lengths of he diagonals

we do

(9+3) times (3√3) to find the area total which is 36√3

then, we find teh area of the sector not shaded

the area of the sector is (120/360) times the area which is pi6^2

so

1/3 times 36pi or 12pi

so

36√3-12pi≈24.6547 square units

se diagram

so using my math

remember that if the hyptonuse is 2x then angle oposite the 30 degree is x and angle oposit the 60 degree is x√3

so

we have a kite and know the lengths of he diagonals

we do

(9+3) times (3√3) to find the area total which is 36√3

then, we find teh area of the sector not shaded

the area of the sector is (120/360) times the area which is pi6^2

so

1/3 times 36pi or 12pi

so

36√3-12pi≈24.6547 square units

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QUESTION POSTED AT 01/06/2020 - 04:49 PM

QUESTION POSTED AT 01/06/2020 - 04:47 PM

QUESTION POSTED AT 01/06/2020 - 04:47 PM

QUESTION POSTED AT 01/06/2020 - 04:46 PM

QUESTION POSTED AT 01/06/2020 - 04:45 PM