The specific heat of liquid water is 4.184 j/g· ?c. calculate the energy required to heat 10.0 g of water from 26.5?c to 83.7?c. 1. 572 j 2. 837 j 3. 2.39 × 103 j 4. none of these 5. 239 j

QUESTION POSTED AT 18/04/2020 - 05:40 PM

Answered by admin AT 18/04/2020 - 05:40 PM

Energy required=mass*specific heat*temperature change
=10*4.184*57.2
=2393.248j
=2.39*10^3
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