How much would the freezing point of water decrease if 4 mol of NaCl were added to 1 kg of water (Kf = 1.86°C/(mol/kg) for water and i = 2 for NaCl)?

Answered by admin AT 18/04/2020 - 06:15 PM

When a solute is added to a solvent, some properties are affected and these set of properties are called colligative properties. The properties depend on the amount of solute dissolved in a solvent. For freezing point depression, we calculate as follows:

ΔT(freezing point) = (Kf)m
ΔT(freezing point) = 1.86 °C kg / mol (4 mol / kg)
ΔT(freezing point) = 7.44 °C
Tf - T = 7.44 °C
T = -7.44 °C

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QUESTION POSTED AT 01/06/2020 - 04:18 PM

How much would the freezing point of water decrease if 4 mol of NaCl were added to 1 kg of water (Kf = 1.86°C/(mol/kg) for water and i = 2 for NaCl)?

Answered by admin AT 18/04/2020 - 06:15 PM

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