# Write a polynomial function of least degree with integral coefficients that has the given zeros of 5 and -2i

QUESTION POSTED AT 18/04/2020 - 06:50 PM

QUESTION POSTED AT 18/04/2020 - 06:50 PM

Hello :

f(x) = (x-5)(x+2i)

= x² +2ix -5x-10i

f(x) = x² +(2i-5)x -10i

coefficients : a =1 b = 2i-5 c =-10i

f(x) = (x-5)(x+2i)

= x² +2ix -5x-10i

f(x) = x² +(2i-5)x -10i

coefficients : a =1 b = 2i-5 c =-10i

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