How many moles of oxygen must be placed in a 3.00 L container to exert a pressure of 2.00 atm at 25.0°C?

QUESTION POSTED AT 18/04/2020 - 07:51 PM

Answered by admin AT 18/04/2020 - 07:51 PM

PV = nRT --> n = PV/RT
n = (2×3)/(.0821×298) = 6/24.47
n = 0.245 moles O2
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