﻿ The titration of 25.0 ml of an iron(ii) solution required 18.0 ml of a 0.205 m solution of dichromate to reach the equivalence point. what is the molarity of the iron(ii) solution? - AssignmentGrade.com

The titration of 25.0 ml of an iron(ii) solution required 18.0 ml of a 0.205 m solution of dichromate to reach the equivalence point. what is the molarity of the iron(ii) solution?

QUESTION POSTED AT 28/05/2020 - 11:50 PM

Answered by admin AT 28/05/2020 - 11:50 PM

The formula of this is : MV = MV or Molarity × Volume = Molarity × Volume. So you do:
25X = 18×.205=.1476M

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