A 3.682 g sample of kclo3 is dissolved in enough water to give 375. ml of solution. what is the chlorate ion concentration in this solution?

QUESTION POSTED AT 29/05/2020 - 12:32 AM

Answered by admin AT 29/05/2020 - 12:32 AM

MKClO₃: 39g+35,5g+(16g×3) = 122,5 g/mol

1 mol -- 122,5g
X mol -- 3,682g
X = 3,682/122,5
X = 0,03 mol

375 ml = 0,375 l = 0,375 dm³

C = n/V
C = 0,03/0,375
C = 0,08 mol/dm³

[ClO₃-] = [KClO₃] = 0,08 mol/dm³
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