A 0.00100 mol sample of ca(oh)2 requires 25.00 ml of aqueous hcl for neutralization according to the reaction below. what is the concentration of the hcl? ca(oh)2(s) + 2hcl(aq) --> cacl2(aq) + h2o(l)

QUESTION POSTED AT 29/05/2020 - 12:35 AM

Answered by admin AT 29/05/2020 - 12:35 AM

Ca(OH)₂ + 2HCl ---> CaCl₂ + 2H₂O
1 mol.........2 mol

1 mol Ca(OH)₂ --- 2 mol HCl
0,001 mol --------- X
X = 0,001×2 = 0,002 mol HCl

25 ml = 0,025 l = 0,025 dm³

C = n/V
C = 0,002/0,025
C = 0,08 mol/dm³
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