Ammonia will react with fluorine to produce dinitrogen tetrafluoride and hydrogen fluoride (used in production of aluminum, in uranium processing, and in frosting of light bulbs). 2nh3(g) + 5f2(g) ? n2f4(g) + 6hf(g). how many moles of nh3 are needed to react completely with 13.6 mol of f2?

QUESTION POSTED AT 29/05/2020 - 12:46 AM

Answered by admin AT 29/05/2020 - 12:46 AM

2NH₃ + 5F₂ ---> N₂F₄ + 6HF
2 mol...5 mol

2 mol NH₃ --- 5 mol F₂
X mol NH₃ ---13,6 mol F₂
X = (2×13,6)/5
X = 5,44 mol NH₃
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