What is the pH of a solution with a hydronium concentration of 2.88 × 10-2 M?

QUESTION POSTED AT 01/06/2020 - 02:42 PM

Answered by admin AT 01/06/2020 - 02:42 PM

PH=-lg[H⁺]

[H⁺]=2.88*10⁻² mol/L

pH=-lg(2.88*10⁻²)=1.54

pH=1.54
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