# What is the length of the hypotenuse, x, if (12, 35, x) is a Pythagorean triple?

QUESTION POSTED AT 01/06/2020 - 02:44 PM

QUESTION POSTED AT 01/06/2020 - 02:44 PM

A^2 + b^2 = c^2

12^2 + 35^2 = x^2

144 + 1225 = x^2

1369 = x^2

sqrt 1369 = x

37 = x.....so the hypotenuse is 37

12^2 + 35^2 = x^2

144 + 1225 = x^2

1369 = x^2

sqrt 1369 = x

37 = x.....so the hypotenuse is 37

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