What are the values of a, b, and c in the quadratic equation -2x^2+4x-3=0

QUESTION POSTED AT 01/06/2020 - 03:22 PM

Answered by admin AT 01/06/2020 - 03:22 PM

Answer:

a=-2\\b=4\\c=-3

Step-by-step explanation:

We know that a standard form of equation in quadratic is

ax^2+bx+c=0

We are given an equation as

-2x^2+4x-3=0

To find a,b and c, it is sufficient to compare the given equation with std form

Comparing -2x^2+4x-3=0 with ax^2+bx+c=0

equate the coefficients of corresponding terms.

So we have

a=-2\\b=4\\c=-3

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