# The locations, given in polar coordinates, for two planes approaching an airport are (4 mi, 12º) and (3 mi, 73º). Find the distance between the two planes.

QUESTION POSTED AT 01/06/2020 - 03:28 PM

QUESTION POSTED AT 01/06/2020 - 03:28 PM

To get the distance between the two planes we use the cosine rule;

c^2=a^2+b^2-2abCosC

thus;'

a=4 miles

b=3 miles

C=73-12=61

thus

c^2=4^2+3^2-2*3*4Cos 61

c^2=16+9-24cos61

c^2=25-24cos61

c^2=13.3646

c=sqrt13.3646

c=3.66 miles

They two planes are 3.66 miles apart

c^2=a^2+b^2-2abCosC

thus;'

a=4 miles

b=3 miles

C=73-12=61

thus

c^2=4^2+3^2-2*3*4Cos 61

c^2=16+9-24cos61

c^2=25-24cos61

c^2=13.3646

c=sqrt13.3646

c=3.66 miles

They two planes are 3.66 miles apart

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