# The line containing the diagonal of a square whose vertices are A(-3, 3), B(3, 3), C(3, -3), and D(-3, -3). Find two equations, one for each diagonal.

QUESTION POSTED AT 01/06/2020 - 04:20 PM

QUESTION POSTED AT 01/06/2020 - 04:20 PM

Attached to the answer is a graph of the square, based on the points given. From there you can easily guess the equations of the diagonal lines.

However, you do not need a graph in order to solve the problem.

AC and BD are two pairs of points diagonally across from one another. This is because the pairs do not share the same x or y value.

**Based on the equation of the line:**

We must find the slope(m) and the y-intercept(b).

**Finding slope (m):**

Lets use the equation below:

**Line AC:**

∴ m = -1

∴

**Line BD:**

∴ m = 1

∴

**Find y-intercept (b):**

In order to find the y-intercept(b) of the line, we must plug in a point that is on that line.

**Line AC:**

y = -1x + b

3 = -1(-3) + b

3 = 3 + b

b = 0

**Line BD:**

y = 1x + b

3 = 1(3) + b

3 = 3 + b

b = 0

Therefore, the equations for the diagonals are as follows:

Hope this helps!

However, you do not need a graph in order to solve the problem.

AC and BD are two pairs of points diagonally across from one another. This is because the pairs do not share the same x or y value.

We must find the slope(m) and the y-intercept(b).

Lets use the equation below:

∴ m = -1

∴

∴ m = 1

∴

In order to find the y-intercept(b) of the line, we must plug in a point that is on that line.

y = -1x + b

3 = -1(-3) + b

3 = 3 + b

b = 0

3 = 1(3) + b

3 = 3 + b

b = 0

Therefore, the equations for the diagonals are as follows:

Hope this helps!

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