A target has a bull’s-eye with a diameter of 2 inches. the outer ring is 1 inch wide. what is the area of the outer ring?

QUESTION POSTED AT 01/06/2020 - 05:09 PM

Answered by admin AT 01/06/2020 - 05:09 PM

The diameter of the outer ring will be 4 inches since it extends one inch beyond the bull's eye from either side. See the attached image for clarification.

The area of the outer ring can be expressed as:
Area_{outerring} = Area_{outercircle} - Area_{bullseye}
This is because we need to take into account of the space taken up by the bullseye. 

Now we set up our equation:
Area_{outerring} =  \pi r^{2}_{outercircle} -  \pi r^{2}_{bullseye}

Now plug and solve:
Area_{outerring} =  \pi 2^{2} -  \pi 1^{2}
Area_{outerring} =  4\pi -  \pi
Area_{outerring} = 9.42477796

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QUESTION POSTED AT 01/06/2020 - 04:46 PM