# Find the derivative of the following functions f(x) = x^7 - 2x^3 - 9x

QUESTION POSTED AT 02/06/2020 - 01:20 AM

QUESTION POSTED AT 02/06/2020 - 01:20 AM

Use the power rule,

d(x^n)/dx = nx^(n-1)

So

f(x)=x^7-2x^3-9x

f'(x)=7x^6-6x^2-9

d(x^n)/dx = nx^(n-1)

So

f(x)=x^7-2x^3-9x

f'(x)=7x^6-6x^2-9

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