# Let y=4x^2 find the differential dy when x=5 and dx=0.4

QUESTION POSTED AT 02/06/2020 - 01:22 AM

QUESTION POSTED AT 02/06/2020 - 01:22 AM

Dy=y'*dx

=8x*dx

=8(5)*0.4

=40*0.4

=16

=8x*dx

=8(5)*0.4

=40*0.4

=16

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