# Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2

QUESTION POSTED AT 02/06/2020 - 01:54 AM

QUESTION POSTED AT 02/06/2020 - 01:54 AM

Because each circle has radius = 2 in, each side of the square is 4*2 = 8 in.

The area of the square is 8^2 = 64 in^2

The area of one circle is π*2^2 = 4π in^2

The area of 4 circles is 4*(4π) = 16 in^2

The remaining area of the square is

**(64 - 16π) in^2**

The area of the square is 8^2 = 64 in^2

The area of one circle is π*2^2 = 4π in^2

The area of 4 circles is 4*(4π) = 16 in^2

The remaining area of the square is

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