The solution to the given system of linear equations lies in which quadrant? x-3y=6 x+y=2

QUESTION POSTED AT 02/06/2020 - 01:57 AM

Answered by admin AT 02/06/2020 - 01:57 AM

X - 3y = 6
x + y = 2 ....multiply by -1
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x - 3y = 6
-x - y = -2 (result of multiplying by -1
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-4y= 4
y = -4/4
y = -1

x - 3y = 6
x - 3(-1) = 6
x + 3 = 6
x = 6 - 3
x = 3

solution is (3,-1)

Quadrant IV contains points (+,-)......so ur points fall in quadrant 4
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