The perimeter of a rectangular field is 264 yards. If the length of the field is 74 yards, what is the width?

QUESTION POSTED AT 05/12/2019 - 11:40 AM

Answered by admin AT 05/12/2019 - 11:40 AM

58 yards

P=2l x 2w
264=2(74) x 2w
264=148 x 2w

264-148=116
116/2 = 58
Post your answer

Related questions

What is the volume of a rectangular crate that has dimensions 9 inches by 9 inches by 1 feet?

1 feet = 12 inches
so the formula is: length x width x height
now substitute in the values: 9 x 9 x 12
and the answer is: 972 inches cubed

hope it helped :)

ANSWERED AT 22/01/2020 - 02:25 AM


QUESTION POSTED AT 22/01/2020 - 02:25 AM

Equilateral triangle ABC has a perimeter of 96 millimeters. A perpendicular bisector is drawn from angle A to side at point M. What is the length of ?

Apply heron's formula to get the area of the triangle.
since it is an equilateral triangle, we know that each side is 32mm.
we get the length of the line (h) from area = bh/a

27.7

ANSWERED AT 22/01/2020 - 02:19 AM


QUESTION POSTED AT 22/01/2020 - 02:19 AM

Find the perimeter of rectangle PQRS with vertices P(0,0), Q(0,7), R(12,7) & S (12,0)

P=7+7+12+12P=14+24P=38

See the attachment for diagram

ANSWERED AT 22/01/2020 - 02:17 AM


QUESTION POSTED AT 22/01/2020 - 02:17 AM

A square is inscribed in a circle that has a radius of 2√2 inches. What is the length of the side of the square?

When a square (or any rectangle) is inscribed in a circle, the diagonal
of the square (or rectangle) is a diameter of the circle.

Diagonal of this square = diameter = 2 x radius = 4√2 inches.

But the diagonal of a square is the hypotenuse of the right triangle that's
formed by cutting the square in half corner-to-corner.

So  (diagonal)²  =  (side)²  +  (side)²

           2 (side)² = (diameter)²

           2 (side)²  =  (4√2)²

           2 (side)²  =  16 x 2 = 32

              (side)²  =  16

               side  =    4 inches

ANSWERED AT 22/01/2020 - 02:02 AM


QUESTION POSTED AT 22/01/2020 - 02:02 AM

A) The area of a rectangle is 38.25 square yards and its base is 9 yards. What is the height? Do not round your answer.B) The area of a parallelogram is 44.4 square feet and its height is 7.4 feet. What is the length of the base? Do not round your answer.

A). area of a rectangle equal length time width 

in this case 

38,25 = 9*h

h = 38,25/9 = 4,24 

B). area of a parallelogram equal 44,4 square feet and its height is 7,4 feet

Area = length of base time height 

44,4 = l * 7,4

l = 44,4 / 7,4 = 6 ft

ANSWERED AT 22/01/2020 - 01:59 AM


QUESTION POSTED AT 22/01/2020 - 01:59 AM

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown. Which best describes the range of possible values for the third side of the triangle? x < 12.5, x > 18.9 12.5 < x < 18.9 x < 6, x > 26 6 < x < 26

So because we know that the 3rd side of a triangle not can being less than the difference of the first and second sides and so not can being greater than the sum of the first and second sides so from these result that the last one choice will be right sure 

6 < x < 26

ANSWERED AT 22/01/2020 - 01:52 AM


QUESTION POSTED AT 22/01/2020 - 01:52 AM

The lengths of two sides of a right triangle are 5 inches and 8 inches. What is the difference between the two possible lengths of the third side of the triangle? Round your answer to the nearest tenth.

Let x be the third side. The two cases that allow us to determine the length of the third side are: (1) let x be the hypotenuse and (2) let 8 be the hypotenuse and solve for x. Through the Pythagorean theorem,
 
Case 1.           x² = 8² + 5²       ; x = 9.4
Case 2.           8² = x² + 5²       ; x = 6.2

Thus, the difference is approximately 3.2.

ANSWERED AT 22/01/2020 - 01:52 AM


QUESTION POSTED AT 22/01/2020 - 01:52 AM

An isosceles right triangle has leg lengths of 4 centimeters. What is the length of the altitude drawn from the right angle to the hypotenuse? 2 cm cm 4 cm cm

See the picture attached to better understand the problem

we know that
AB=4cm \\ AC=4 cm

in the right triangle ADB
angle DBA=angle DAB \\ =45 degrees
cos (DAB)= \frac{AD}{AB}
where
AD is the adjacent side angle DAB (altitude)
AB is the hypotenuse triangle ADB 
Angle DAB=45°
so
solve for AD
AD=AB*cos (45)
AD=4* \frac{ \sqrt{2}}{2} \\ AD=2 \sqrt{2} cm

therefore

the answer is 
the length of the altitude is 2 \sqrt{2} cm

ANSWERED AT 22/01/2020 - 01:43 AM


QUESTION POSTED AT 22/01/2020 - 01:43 AM

A rectangle’s width is 2 meters shorter than its length, l. Its area is 168 square meters. Which equation can be used to find the length of the rectangle? l(l – 2) = 168 l(l + 2) = 168 2l 2 = 168 1/2 l 2 = 168

The area (A) of the triangle is the product of its length (l) and width (w). A = l x w. Since the width is 2 m shorter than the length, it may be expressed as w = l -2. The equation for area becomes,
                          A = l x (l - 2)
Substituting the known area and rearranging the equation gives,
                           l(l - 2) = 168.

ANSWERED AT 22/01/2020 - 01:36 AM


QUESTION POSTED AT 22/01/2020 - 01:36 AM

A triangle has two sides of lengths 6 and 9. What value could the length of the the third side be? Check all that apply A.15 B.4 C.7 D.2 E.12 F.10

Knowed that the 3rd side of a triangle need being greater than the difference of the given two sides length and less that the sum of the given two sides length 
so with these knowledge we get 
x > (9-6) so x > 3
and 
x < (9+6) so x < 15

from these result that the 3rd side length can being choice B. 4 ,C. 7,F. 10,
E. 12,

hope this will help you 

ANSWERED AT 22/01/2020 - 01:33 AM


QUESTION POSTED AT 22/01/2020 - 01:33 AM

The area of a playground is 234 yd2. The width of the playground is 5 yards longer than its length. Find the length and width of the playground. (1 point)

Let x be the length of the playground. With this representation, the width may be expressed as x + 5. The area of a rectangular figure is the product of its length and width. 
 
                                              A = L x W
 
                                     A = (x)(x+5) = 234 yd²

Solving for the value of x in the equation gives an answer of x = 13 and x = -18. The second value of x is not applicable to the problem since a negative number cannot be a value for length. Below is the calculation of the dimensions.

                                     Length = x = 13 yards 
                                   Width = x + 5 = 18 yards

Thus, the length and width of the playground are 13 and 18 yards, respectively. 


ANSWERED AT 22/01/2020 - 01:28 AM


QUESTION POSTED AT 22/01/2020 - 01:28 AM

For a 25 inch television screen, the length of the screen's diagonal is 25 inches. If the screen's height is 15 inches, what is the width?

The length (L), width (W), and the diagonal (D) of the television screen make a right triangle with the legs L and W and hypotenuse D. Thus, their measurements are related through Pythagorean Theorem.
 
                                          L² + W² = D²

Substituting the known values from the given,
 
                                        (15 in)² + W² = (25 in)²

Solving for W in the equation gives, W = 20 in and W = -20. The second value is an extraneous root. Thus, the width of the television screen is 20 inches.

ANSWERED AT 22/01/2020 - 01:27 AM


QUESTION POSTED AT 22/01/2020 - 01:27 AM

Which of the following is true about the median of a trapezoid? A. The median is half the length of the largest base. B. The median connects the midpoints of the legs of a trapezoid. C. The median connects the midpoints of the bases of a trapezoid. D. The median is twice the length of the smallest base.

The only choice that describes truthfully the median is choice letter B. This states that the median connects the midpoints of the legs of a trapezoid. The legs are most commonly referred as the nonparallel sides as the other two sides are parallel. 

ANSWERED AT 22/01/2020 - 01:26 AM


QUESTION POSTED AT 22/01/2020 - 01:26 AM

What is the volume of a rectangular prism that is 35 meters by 15 meters by 22 meters?

The volume of a rectangular prism is simply the product when all its dimensions: length, height and width are multiplied. 
 
                                   A = L x W x H 
 
                             A = 35 m x 15 m x 22 m = 11550 m³. 

Therefore, the volume of the prism is 11550 m³.


ANSWERED AT 22/01/2020 - 01:24 AM


QUESTION POSTED AT 22/01/2020 - 01:24 AM

A square picture with a side length of 4 inches needs to be enlarged. The final area needs to be 81 square inches. Which equation can be used to solve for x, the increase in side length of the square in inches? x^2 + 4x – 81 = 0 x^2 + 4x – 65 = 0 x^2 + 8x – 65 = 0 x^2 + 8x – 81 = 0

Each side of the square needs to be enlarged by x inches to obtain the new area which is 81. The area of the square is calculated by squaring the measure of its side. 
                                         A = (x + 4)²
From the given value of area,
                                          (x +  4)² = 81
                                     x ² + 8x + 16 = 81
          
Further simplification leads to the answer,
                                         x² + 8x - 65 = 0
                        
                                      

ANSWERED AT 22/01/2020 - 01:20 AM


QUESTION POSTED AT 22/01/2020 - 01:20 AM

The length of the sides of four triangles are given. Determine which triangle is not a right triangle.a.5 mm, 12 mm, 13 mmb.20 mm, 48 mm, 52 mmc.6 mm, 8 mm, 10 mmd.11 mm, 24 mm, 26 mm

For a right triangle, the sum of the squares of two shorter side should be equal to the square of the third side. The calculations for each choices are shown below. 

a. (5 mm)² + (12 mm)² = 169 mm²    ;    (13 mm)² = 169 mm²   ;     EQUAL
b. (20 mm)² + (48 mm)² = 2704 mm²   ; (52 mm)² = 2704 mm²  ;    EQUAL
c. (6 mm)² + (8 mm)² = 100 mm²       ;    (10 mm)² = 100 mm²   ;     EQUAL
d. (11 mm)² + (24 mm)² = 697 mm² ;  (26 mm)² = 676 mm²  ;  NOT EQUAL

Therefore, the answer is letter D. 

ANSWERED AT 22/01/2020 - 01:18 AM


QUESTION POSTED AT 22/01/2020 - 01:18 AM

A pencil manufacturer has a certain tolerance for the actual lengths of the pencils it produces. After the pencils are manufactured, a 1.1 centimeter eraser is added to one end of the pencil. The total length of each pencil must be between 12.9 cm and 13.3 cm. Write an inequality representing the possible lengths of the pencils before the erasers have been added, and then find the lengths.

The statement could be best express using the equation 12.9 < x + 1.1cm > 13.3 . This is express using that equation  because it states that the minimum length for the pencil is 12.9 and the maximum length is 13.3. Also, it states that the length of the pencil (x) will have an additional length becuase of eraser which is 1.1, x +11. 

ANSWERED AT 22/01/2020 - 01:12 AM


QUESTION POSTED AT 22/01/2020 - 01:12 AM

The length of a rectangle is 5 centimenters less than twice its width. the perimeter of the rectangle is 26 cm. what are the demisions of the rectangle

L = w - 5
2*l + 2*w = 26
2*(w - 5) + 2*w = 26
2w - 10 + 2w = 26
4w = 36
w = 9
l = w - 5
l = 9 - 5
l = 4

Final Answer:
The rectangle is 4cm long and 9cm wide.
Hope I helped :)

ANSWERED AT 22/01/2020 - 01:05 AM


QUESTION POSTED AT 22/01/2020 - 01:05 AM

A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of _____ square units.

Given the apothem (a) and the side of the regular polygon, the area (A) of the polygon may be calculated by the formula, 
     
                                 A = aP/2

where P is the perimeter. 

Given that the octagon has a length of 11, its perimeter is 88. Substituting this to the formula above, 
 
                                A = (8.85)(88) / 2 = 389.4

Thus, the area of the polygon is 389.4 unit².
 

ANSWERED AT 22/01/2020 - 01:04 AM


QUESTION POSTED AT 22/01/2020 - 01:04 AM

Tamara is creating a model of a rectangle. She has 26 inches of yellow ribbon to use for the border of the rectangle. She wants the length, l, to be 3 inches greater than the width, w. Which system of equations could Tamara use to find the dimensions of a rectangle that uses all of the ribbon?

Let

L-------> the length of the rectangle

W------> the width of the rectangle

we know that

the perimeter of the rectangle is equal to

P=2L+2W

P=26\ in -----> because Tamara's using the whole ribbon

so

26=2L+2W -------> equation A

L=W+3 -------> equation B

Substitute equation B in equation A

26=2(W+3)+2W

26=2W+6+2W

4W=26-6

W=5\ in

find the value of L

L=W+3=5+3=8\ in

therefore

the answer is

The system of equations is

26=2L+2W

L=W+3

ANSWERED AT 22/01/2020 - 01:00 AM


QUESTION POSTED AT 22/01/2020 - 01:00 AM

Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of the run 20 feet. She writes and solves the equation 2l + 2w = 62 to find the width of the run.

You have asked no question.

I am ASSUMING you want to know how to solve the equation to learn the width.

2L + 2W = 62

2(20) + 2W = 62

    40 + 2W = 62

            2W = 22

              W = 11


ANSWERED AT 22/01/2020 - 12:54 AM


QUESTION POSTED AT 22/01/2020 - 12:54 AM

Find the perimeter and area of a rectangle with a length of 5 cm and a diagonal of 13 cm

Use the Pythagorean Theorem to find the other side length, as the triangle formed by the 5cm and the 13cm side is a right triangle.
5^2 + ?^2 = 13^2
25 + ?^2 = 169
?^2 = 169 - 25
?^2 = 144
? = 12
Now you know the rectangle is 5cm by 12cm, you can find the area by multiplying the two, and the perimeter by doubling both then adding.
Final Answer:
area = 5 * 12 = 60cm^2
perimeter = 5*2 + 12*2 = 34cm 
Hope I helped :)

ANSWERED AT 22/01/2020 - 12:53 AM


QUESTION POSTED AT 22/01/2020 - 12:53 AM

Find the perimeter and area of a rectangle with a length of 6 feet and a diagonal of 10 feet

Use the Pythagorean Theorem to find the other side length, as the triangle formed by the 6ft and the 10ft side is a right triangle.
6^2 + ?^2 = 10^2
36 + ?^2 = 100
?^2 = 100 - 36
?^2 = 64
? = 8
Now you know the rectangle is 6ft by 8ft, you can find the area by multiplying the two, and the perimeter by doubling both then adding.
Final Answer:
area = 6 * 8 = 48ft^2
perimeter = 6*2 + 8*2 = 28ft 
Hope I helped :)

ANSWERED AT 22/01/2020 - 12:52 AM


QUESTION POSTED AT 22/01/2020 - 12:52 AM

Nash is making a framed enlargement of a Mary Cassatt postage stamp to present to a retired postmaster. He enlarges the stamp using a scale of 2 inches to 1 centimeter. If the actual length of the stamp is 3 centimeters and its width is 5 centimeters, what are the dimensions of the scale picture?

Answer: 6 by 10 inches


Step-by-step explanation:

Given: Nash is making a framed enlargement of a Mary Cassatt postage stamp to present to a retired postmaster.

The scale of enlargement is 2 inches to 1 centimeter.

The actual length of the stamp = 3 centimeters

The length of frame = 2\times3=6\ inches

The actual width of the stamp = 5 centimeters

The width of frame = 2\times5=10\ inches

Thus, the dimension fo the scale picture is 6 by 10 inches



ANSWERED AT 22/01/2020 - 12:49 AM


QUESTION POSTED AT 22/01/2020 - 12:49 AM