The perimeter of a rectangular pool 160 meters. The length of the pool is 20 meters more than it's width. What is the length?

QUESTION POSTED AT 05/12/2019 - 02:44 PM

Answered by admin AT 05/12/2019 - 02:44 PM

Width=w
Length=l
Perimeter=p

p=2w+2l
l=20+w
p=2w+20+w+20+w
p=4w+40

4w+40=160
4w=160-40=120
w=120:4=30
w=30
l=20+w
l=20+30=50
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Related questions

Find the quotient. (6x 2 + 23x + 20) ÷ (5 + 2x) 3x - 4 3x + 4 3x +19

\frac{6x^{2} + 23x + 20}{2x + 5} = \frac{6x^{2} + 15x + 8x + 20}{2x + 5} = \frac{3x(2x) + 3x(5) + 4(2x) + 4(5)}{2x + 5} = \frac{3x(2x + 5) + 4(2x + 5)}{2x + 5} = \frac{(3x + 4)(2x + 5)}{2x + 5} = 3x + 4

The answer is B.

ANSWERED AT 18/01/2020 - 01:13 PM


QUESTION POSTED AT 18/01/2020 - 01:13 PM

The Martin family is considering building a new house. On the blueprints, the dimensions of the outside of the house are 18 inches wide by 26 inches long. If the house is actually going to be 45 feet wide, what will the actual length of the house be?

This can be answered through simple ratio and proportion

 

Let x = width

y = height

x/y = x2/y2 = x3/y3

 

since

for 18 inches width we have 26 inches as length, therefore

 

18/26 = 45/y2

y2 = 65 ft

 

there is no need to convert the units for the smaller dimensions since we are dealing with definite ratios thus unitless. 

ANSWERED AT 18/01/2020 - 01:12 PM


QUESTION POSTED AT 18/01/2020 - 01:12 PM

20% of the people left and 76 remain, how many people were there?

Percent porportion 76 over x and 20 over 100  mutply 76x100 then divide by 20 x= youre anwser

ANSWERED AT 18/01/2020 - 01:09 PM


QUESTION POSTED AT 18/01/2020 - 01:09 PM

To solve the equation - 4 = 20, you would first add 4 to each side and then divide each side by 8. True False

False, just divide 20 by -4 to get correct answere.

ANSWERED AT 18/01/2020 - 01:08 PM


QUESTION POSTED AT 18/01/2020 - 01:08 PM

How does this model demonstrate the Pythagorean Theorem? Three squares whose corners touch so that the respective edges form a triangle. The smallest square has a side labeled six and is made up of thirty-six smaller squares. The largest square has a side labeled ten and is made up of one hundred smaller squares. The third square has a side labeled eight and is made up of sixty-four smaller squares. A. The sum of the lengths of the shortest and the longest sides is equal to twice the length of the middle side. So double the length of the longer leg of any right triangle is equal to the sum of the shorter leg and the hypotenuse. B. The sum of the area of the two smaller squares is equal to the area of the larger square. So the sum of the lengths of the two legs of any right triangle squared is equal to the length of the hypotenuse squared. C. The sum of the area of the smallest and the largest squares is equal to the area of the middle square. So the sum of the lengths of the shorter leg and the hypotenuse of any right triangle squared is equal to the length of the middle leg squared. D. The length of the longest side minus two equals the length of the middle side. The length of the middle side minus two equals the length of the shortest side. So the length of the short leg of any right triangle is equal to the length of the middle leg minus 2, and the length of the hypotenuse is equal to the length of the middle leg plus 2.

"  B is your best choice but it is very badly stated. this gives an Example of the Pythagorean theorem. it does Not demonstrate it. B is written incorrectly, it should say "sum of squares of the lengths of the legs" Not "sum of the lengths of the two legs of any right angle squared"

ANSWERED AT 18/01/2020 - 01:07 PM


QUESTION POSTED AT 18/01/2020 - 01:07 PM

Triangle ABC has side lengths 18,24, and 30. Do the side lengths form a Pythagorean triple? Yes or No?

Answer:  Yes, the side lengths form a pythagorean triple.

Step-by-step explanation:  Given that the side lengths of triangle ABC are as follows :

AB=18,~~BC=24,~~CA=30.

We are to check whether the side lengths form a pythagorean triple or not.

For making a pythagorean triple, the side lengths must satisfy the following :

AB^2+BC^2=CA^2.

We have

AB^2=18^2=324,\\\\BC^2=24^2=576,\\\\CA^2=30^2=900.

So,

AB^2+BC^2=324+576=900=CA^2.

Thus, the side lengths will form a pythagorean triple.

ANSWERED AT 18/01/2020 - 01:06 PM


QUESTION POSTED AT 18/01/2020 - 01:06 PM

Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work. (5 points)

16x2−4x−4x+1=4x(4x−1)−1(4x−1)=(4x−1)(4x−1)=(4x−1)2 Length of each side=4x-1

ANSWERED AT 18/01/2020 - 12:54 PM


QUESTION POSTED AT 18/01/2020 - 12:54 PM

Which expression is equivalent to 8a + 20? A. 4(2a + 20) B. 4(2a + 5) C. 4(4a + 16) D. 4(4a + 5)

B since 4 times 2 is 8 and 4 times 5 is 20

ANSWERED AT 18/01/2020 - 12:54 PM


QUESTION POSTED AT 18/01/2020 - 12:54 PM

Andrew bought 3 baseball cards for $240. After a few months, he got an offer from his friend Jack to buy the first card for double its original value, along with either the second or third card. Andrew decided to sell the first card (at double its original value) along with the second card (at its original price) and got $320 for it. Or, selling the first card (at double its original value) card along with the third card (at its original price) would have only got him $280. What were the original prices for each of the 3 baseball cards? A-(80, 120, 40) B-(80, 130, 30) C-(130, 90, 20) D-(120, 80, 40)

Answer:

Option D. (120, 80, 40)

Step-by-step explanation:

Let the cost of 3 baseball cards bought by Andrew are $x, $y and $z.

Now we will form the equations to find the unknown values of x, y, and z.

Statement 1 - Andrew bought 3 baseball cards for $240

Equation will be (x + y + z) = 240 --------(1)

Statement 2 - Jack offered a deal to buy the first card for the double of its original value along with the second card for $320.

Equation will be 2x + y = 320 --------(2)

Statement 3 - Jack offered another deal to buy first card for the double of its original value along with third card for $280

Equation formed 2x + z = 280 ------(3)

Now we can solve these equations to get the values of x, y and z.

From equation 2

y = 320 - 2x

From equation 3

z = 280 - 2x

Now we can replace the values of y and z in equation number 1.

Equation 1 becomes after substitution of y and z values

x + (320 - 2x) + (280 - 2x) = 240

Now we will group the similar terms

(x - 2x - 2x) + (320 + 280) = 240

-3x + 600 = 240

-3x = 240 - 600

-3x = - 360

x = \frac{360}{3}

x = 120

Now  we put x = 120 in the value of y

y = 320 - 2x

y = 320 - 2×120

  = 320 - 240

  = 80

Similarly we put the value x = 120 in value of z

z = 280 - 2x

  = 280 - 2×120

  = 280 - 240

  = 40

So the original values of 3 baseball cards are (120, 80, 40)

Option D. will be the answer.

ANSWERED AT 18/01/2020 - 12:53 PM


QUESTION POSTED AT 18/01/2020 - 12:53 PM

The lengths of three line segments are 4 centimeters, 5 centimeters, and 9 centimeters. Using this information, triangles can be constructed.

Answer:

No triangles can be constructed

Step-by-step explanation:

we know that

The Triangle Inequality Theorem, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

so

In this problem

4+5>9------> is not true

therefore

No triangles can be constructed with the given side lengths



ANSWERED AT 18/01/2020 - 12:46 PM


QUESTION POSTED AT 18/01/2020 - 12:46 PM

Two sides of an obtuse triangle measure 10 inches and 15 inches. The length of longest side is unknown. What is the smallest possible whole-number length of the unknown side?

Answer – 19 inches
 The smallest possible whole-number length of the longest side of an obtuse triangle is the next integer greater than the Pythagorean distance of the other two sides.
 Given,
A = 10
 B = 15
Pythagoras theorem;
C^2 = A^2 + B^2
C^2 = 15^2 + 10^2
C^2 = 225 + 100
C^2 = 325
C = 18.03
 Therefore, the smallest possible whole-number length of the longest side is the next integer greater than 18.03 inches.
The smallest possible whole-number length of the longest side is 19 inches

ANSWERED AT 18/01/2020 - 12:45 PM


QUESTION POSTED AT 18/01/2020 - 12:45 PM

Mary is making some shirts for her school's drama department. The fabric store has 3 1/6 yards of the fabric she wants in stock. But this quantity of fabric can make only 1 1/3 shirts. What length of fabric does Mary need to buy if she wants to sew 2 shirts?

The answer is 4 3/4 yards of the fabric.

This can be calculated using the proportion.
If the 3 1/6 yards of the fabric is enough for 1 1/3 shirts, how many yards are necessary of 2 shirts:
3 \frac{1}{6} yards :1 \frac{1}{3}shirts =xyards:2shirts

Let's express 3 1/6 as 19/6:
3 \frac{1}{6} =3+ \frac{1}{6} = 3* \frac{6}{6}+ \frac{1}{6} = \frac{18}{6} + \frac{1}{6} = \frac{18+1}{6} = \frac{19}{6}

Similarly, 1 1/3 = 4/3:
1 \frac{1}{3} =1+ \frac{1}{3} = 1* \frac{3}{3}+ \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{3+1}{3} = \frac{4}{3}<span>

ANSWERED AT 18/01/2020 - 12:37 PM


QUESTION POSTED AT 18/01/2020 - 12:37 PM

In right ∆ABC, m B = 90°, m C = 40°, and BC = 10. What are the other two side lengths of the triangle?

It could be alot the easest is 20° and 20°

ANSWERED AT 18/01/2020 - 12:32 PM


QUESTION POSTED AT 18/01/2020 - 12:32 PM

Xz is 15 and the perimeter of triangle xwz is 50 what is the length of wz

Well if you have a congruent lines, and you have P = 50 and xz = 15 P = xz + 2 * wz so to find wz you need to subtract xz and divide by 2 50 - 15 = 35 and then divide by 2 to get 17.5

ANSWERED AT 18/01/2020 - 12:26 PM


QUESTION POSTED AT 18/01/2020 - 12:26 PM

Solve the problem. Find the diameter of a circle that has a circumference of 942 meters.

The answer to the problem is 299.85 m.

ANSWERED AT 18/01/2020 - 12:26 PM


QUESTION POSTED AT 18/01/2020 - 12:26 PM

B is the midpoint of ZA. find the length of ZA

If it was more details, it would be easier to solve. But I can suggest a logical way. ZB + BA = ZA. If B is the midpoint it devides line on two equal lines.

ANSWERED AT 18/01/2020 - 12:25 PM


QUESTION POSTED AT 18/01/2020 - 12:25 PM

Miriam has 62 feet of fencing to make a rectangular vegetable garden. Which dimensions will give Miriam the garden with greatest area

6 feet by 10 feet would use 60 feet of fencing. that's the biggest I can think of without going over 62 feet


ANSWERED AT 18/01/2020 - 12:15 PM


QUESTION POSTED AT 18/01/2020 - 12:15 PM

Miriam has 62 feet of fencing to make a rectangular vegetable garden. Which dimensions will give Miriam the garden with greatest area.

Given: 
62 feet of fencing = perimeter

P = 2 (L + W)

62/2 = 31
16 + 15 = 16 * 15 = 240 ft²
17 + 14 = 17 * 14 = 238 ft²
18 + 13 = 18 * 13 = 234 ft²
19 + 12 = 19 * 12 = 228 ft²
20 + 11 = 20 * 11 = 220 ft²

The best dimensions that will give the greatest area is to have a length of 16 feet and a width of 15 feet.

ANSWERED AT 18/01/2020 - 12:15 PM


QUESTION POSTED AT 18/01/2020 - 12:15 PM

The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 variables. Use substitution to solve the problem

Let us assume the width of the rectangle = w
Let us assume the length of the rectangle = l
Then
l = 2w
Also 
Perimeter of the rectangle = 2 (l + w)
24 = 2 (2w + w)
24 = 2 (3w)
24 = 6w
w = 24/6
    = 4 inches
Now 
The length of the rectangle = 2w
                                            = 2 * 4 inches
                                            = 8 inches
So the length of the rectangle is 8 inches and the width is 4 inches.

ANSWERED AT 18/01/2020 - 12:13 PM


QUESTION POSTED AT 18/01/2020 - 12:13 PM

How many different arrangements can be made with the letters in the word POWER? 100 20 120 25

120 different arrangements

ANSWERED AT 18/01/2020 - 12:13 PM


QUESTION POSTED AT 18/01/2020 - 12:13 PM

Which expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign? A square shaped traffic sign is shown with length of one side labeled as 8x minus 2.

Given:
square shaped traffic sign. side measure of 8x - 2

A square has 4 equal sides. To find the area of a square, simply square the measure of 1 side. 

Area of a square = a²
A = (8x-2)²
A = (8x-2)(8x-2)
A = 8x(8x-2) - 2(8x-2)
A = 64x² - 16x - 16x + 4
A = 64x² - 32x + 4




ANSWERED AT 18/01/2020 - 12:13 PM


QUESTION POSTED AT 18/01/2020 - 12:13 PM