**Answer:**

** (D) p = 50.55 (Round to the nearest hundredth).**

**Step-by-step explanation:**

Given: Right triangle SIP such that i = 54 and s = 19.

To find: Which of the following statements are true, round to the nearest hundredth.

Solution: We have given that Right triangle SIP , i = 54 and s = 19.

** By the Pythagoras theorem (IP)²+(SI)² = (SP)².**

Plugging the values

(19)²+(p)² = (54)².

361+(p)² =2916

On subtracting both side by 361.

(p)²+ 361 - 361 =2916 -361

(p)² = 2555

Taking square root both sides .

√(p)² = .

p = 50.547

p = 50.55 (Round to the nearest hundredth).

**Therefore, (D) p = 50.55 (Round to the nearest hundredth).**