What is the perimeter of a rectangle with a width of 23.6 cm and a length of 52.9 cm? A. 76.5 cm B. 100.1 cm C. 153 cm D. 180 cm

QUESTION POSTED AT 18/01/2020 - 07:04 AM

Answered by admin AT 18/01/2020 - 07:04 AM

C because 23.6 times two is 47.4 and 52.9 times two is 105.8, add those two together to get c
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Related questions

What is the area of a rectangle ?

Area of a rectangle is the length x width.

If you had a rectangle with the side measurements of 2in. and 4in. your area would be 8in. squared

ANSWERED AT 20/02/2020 - 10:57 PM


QUESTION POSTED AT 20/02/2020 - 10:57 PM

Find area of a rectangle with vertices -9,3 -9,-7 -6,-7 and -6,-3

4 times 3 equals 12.

ANSWERED AT 20/02/2020 - 10:53 PM


QUESTION POSTED AT 20/02/2020 - 10:53 PM

Two sides of a triangle measure 5 in. and 12 in. Which could be the length of the third side? 3 in. 6 in. 10 in. 18 in.

Answer:

The possible answer is 10 in.

Step-by-step explanation:

Two sides of a triangle measure 5 in. and 12 in.

If three side of triangle are a, b and c then sum of two side is always greater than third side.

Sum of two side greater than third side.  

a+b>c

a+c>b

b+c>a

Difference of two side is less than third side.

a-b<c

b-c<a

a-c<b

Here, we are given two sides of a triangle 5 in and 12 in.

Possible length of third side be

12-5 < c < 12+5

7<c<17

Third side must be lie between 7 to 17.

According to option, Third side must be equal to 10 in.

Hence, The possible answer is 10 in.

ANSWERED AT 20/02/2020 - 10:45 PM


QUESTION POSTED AT 20/02/2020 - 10:45 PM

Nine square tiles are laid out on a table so that they make a solid pattern. perimeters of the fiques that you can be formed?

Let the side of one square be x.
The maximum perimeter will be when the squares will be lined end to end.
This will be:
x + 9x + 9x + x
= 20x

The perimeter of the figures formed will be less than or equal to 20x.

ANSWERED AT 20/02/2020 - 10:41 PM


QUESTION POSTED AT 20/02/2020 - 10:41 PM

A square photograph has a perimeter of 20 inches. What is the area of the photograph?

Answer:

Area of square is 25 inches²

Step-by-step explanation:

Given : A square photograph has a perimeter of 20 inches.

We have to find the area of the photograph.

We know perimeter of square is 4a , where a is side of square

Given : perimeter of square = 20 inches

4a = 20

Divide both side by 4, we get,

a = 5 inches

Also, Area of square = side × side

Area of square = 5 × 5

Area of square = 25 inches²

Thus, area of square is 25 inches²

ANSWERED AT 20/02/2020 - 10:38 PM


QUESTION POSTED AT 20/02/2020 - 10:38 PM

Eight 3 inch squares are put end to end to form a rectangle. What is the distance around?

Well, if you're talking about the perimeter when you stack them together, it would be 54 inches.

ANSWERED AT 20/02/2020 - 10:33 PM


QUESTION POSTED AT 20/02/2020 - 10:33 PM

An equilateral triangle has a perimeter of 48 centimeters. If the triangle is dilated by a factor of .75 ,what is the length of each side of the new triangle?

Length of triangle 48/3=16
75/100*16=12
length of new triangle=16+12=28

ANSWERED AT 20/02/2020 - 10:33 PM


QUESTION POSTED AT 20/02/2020 - 10:33 PM

A square is inscribed within another square by connecting the midpoints of the larger square. The edge length of the outer square is x. Express the area of the inner square as a function of x.

Each edge of the inner square has a length of √[(x/2)²+(x/2)²]=√2x²/4=(x√2)/2
Then, the area is 2x²/4=x²/2 ☺☺☺☺

ANSWERED AT 20/02/2020 - 10:32 PM


QUESTION POSTED AT 20/02/2020 - 10:32 PM

Find the perimeter of the triangle shown ( need fast)

You just add all of the sides together

4.5+5.5+6= 16in.

ANSWERED AT 20/02/2020 - 10:31 PM


QUESTION POSTED AT 20/02/2020 - 10:31 PM

The length of a car is 1/20of the length of the actual car. If the model is 9.3in. long, how long is the actual car?

9.3 x 20 = 186 inches. 12 inches = 1 foot

186 / 12 = 15.5

The actual car is 186 inches, or 15 1/2 feet long.

ANSWERED AT 20/02/2020 - 10:29 PM


QUESTION POSTED AT 20/02/2020 - 10:29 PM

The length of a model car is 1/20 of the length of the actual car. If the model is 8.7 in. long, how long is the actual car?

1/20 is equl to 5% so... 8.7 / 5% =?  or    8.7 / 0.05 = ?

the answer is............ 174 in.

ANSWERED AT 20/02/2020 - 10:26 PM


QUESTION POSTED AT 20/02/2020 - 10:26 PM

Ted has the following triangle dimensions. side length of 8 side length of 14 side length of 23 How many triangles can he construct? A.He can construct only one triangle. B.He can construct two triangles. C.He can construct three triangles. D.He cannot construct a triangle.

Answer:

Step-by-step explanation:

He can not construct a triangle because when you add up two of the side lengths they are supposed to be greater the the remaining side length for example 8+14>23 would be incorrect because 8+14  equals 22 which means it would not be greater than 23 and therefore that is why he can not construct a triangle.

ANSWERED AT 20/02/2020 - 10:22 PM


QUESTION POSTED AT 20/02/2020 - 10:22 PM

One foot is equal to 12 inches. The function I(f) takes a length in feet (as input) and returns a length in inches (as output). I(f) = 12f What is the output of this function if the input is 6?

You need to substitute the number 6 into the function. The output would be 72, because when l(6) = 12(6), you would get l(6) = 72. 

ANSWERED AT 20/02/2020 - 10:16 PM


QUESTION POSTED AT 20/02/2020 - 10:16 PM

The triangle and the trapezoid have the same area.Base b(two) is twice the length of base b( one).What are the lengths of the bases of the trapezoid? Triangle:- b=21 cm &h=6cm. Trapezoid:-h=6cm

Answer:

b2 = 14

b1 = 7

Step-by-step explanation:

Area_triangle = 1/2 * b * h

Area _trapezoid = (b1 + b2)*h1/2

Since the areas of the two figures are the same, we get

1/2 * b * h = (b1 + b2)*h1/2                 multiply both sides by 2.

b*h = (b1 + b2) * h1

b=21

h = 6

2*b1 = b2

21*6 = (b1 + 2*b1)*6                             Divide by 6

21 = 3*b1                                              Divide by 3

7 = b1

2*b1 = b2

b2 = 14

ANSWERED AT 20/02/2020 - 10:11 PM


QUESTION POSTED AT 20/02/2020 - 10:11 PM

A side of one polygon is 18 meters and the corresponding side of a second similar polygon is 24 meters. If the perimeter of the first polygon is 16 meters and it's area is 1000 square meters find the perimeter and area of the similar polygon

The perimeter of a polygon is proportional to its side so:
18 : 16
24 : p
p = 21.3 meters

Area is proportional to the square of the side of a polygon so:
18² : 1000
24² : x
x = 1,777.8 square meters

Note: The value of the perimeter should not be less than the  length of one side. The data may be incorrect. Regardless, the method will be the same.

ANSWERED AT 20/02/2020 - 10:06 PM


QUESTION POSTED AT 20/02/2020 - 10:06 PM

A rectangle prism has a square base of 12 inches and a height of 7 inches. What is the volume of the prism?

1,008 is the answer I got

ANSWERED AT 20/02/2020 - 09:57 PM


QUESTION POSTED AT 20/02/2020 - 09:57 PM

The length of a popcorn machine is 3/4 of it's height. What is the length of the machine?

The length is 18 inches.

Explanation :
The word "of" in math (fractions) means multiplication. So 3/4 x 24 = 18

ANSWERED AT 20/02/2020 - 09:52 PM


QUESTION POSTED AT 20/02/2020 - 09:52 PM

The rotation of q h j 180° about the origin

Could you please give me more of a description?

ANSWERED AT 20/02/2020 - 09:51 PM


QUESTION POSTED AT 20/02/2020 - 09:51 PM

Find the perimeter of the base 10in 6in 18in

If you add them all up the sum of it is 34in

ANSWERED AT 20/02/2020 - 09:46 PM


QUESTION POSTED AT 20/02/2020 - 09:46 PM

(PYTHAGOREAN THEOREM) A diagonal of a cube goes from one of the cube's top corners to the opposite corner of the base of the cube. Find the length to a diagonal d in a cube that has an edge of length 10 meters.

First draw a picture (see attached).

You want to find the diagonal of the cube, length AB.
The right triangle formed is trianagle ABD.
AD = 10m

DB will be the hypotenuse of triangle BCD.
(BC)^2 + (CD)^2 = (DB)^2 \\ &#10;(10)^2 + (10)^2 = (DB)^2 \\&#10;DB =  \sqrt{200}= 10 \sqrt{2}  .

If we know the length of AD and DB, we can find AB.
(AD)^2+(BC)^2 = (AB)^2 \\&#10;(10)^2 + (10 \sqrt{2})^2 = (AB)^2 \\&#10;AB =  \sqrt{300} = 10 \sqrt{3}

In fact, the diagonal of any cube is √3 times the side length of the cube.
Let s be the side length (as in AD or CD in the attached) and
h be the hypotenuse of the base, (DB in the attached) and
d be the diagonal of the cube (AB in the attached).

The hypotenuse of the base will be:s^2+s^2 = h^2 \\&#10;.

The cube's diagonal will be:
h^2+s^2 = d^2.

Substituting s^2+s^2 as h^2, you have
s^2+s^2+s^2 = d^2 \\&#10;3s^2 = d^2 \\&#10;d =  \sqrt{3s^2} =  s\sqrt{3}

ANSWERED AT 20/02/2020 - 09:34 PM


QUESTION POSTED AT 20/02/2020 - 09:34 PM

A diagonal of a cube goes from one of rhe cube's top corners to the opposite corner of the base of the cube. Find the length of a diagonal D in a cube that has an edge of length 10 meters.

So we are trying to find this red line's length.

We can either find it directly, or use the blue line firs, and then use it as a leg for the green triangle.

So the blue leg is a hypotenuse for two of the edges. So:

blue^2 = leg^2 + leg^2 from the Pythagorean Theorem
OR
blue =  \sqrt{leg^2 + leg^2}

Which works out to:

blue =  \sqrt{10^2 + 10^2} =  \sqrt{100+100} = \sqrt{200} =  \sqrt{(100)(2)}=10 \sqrt{2}

So now that we have that, using the Pythagorean Theorem again gives:

red =  \sqrt{blue^2 + 10^2} =  \sqrt{(10 \sqrt{2})^2+10^2}= \sqrt{200+100}= \sqrt{300}
 \sqrt{300}= \sqrt{100*3}=10 \sqrt{3}

So the length of the red line is found that way.

But wait!  There's more!

As it turns out, the red line can be found with an easier way that works with cubes and boxes (cuboids). It's really easy:

a^2 + b^2+c^2=d^2

Where a, b, and c are all 10m, and d is the red line. This greatly reduces the math:

d =  \sqrt{10^2+10^2+10^2} = \sqrt{100+100+100} =  \sqrt{300}

which gives the same answer as above, which you can see.

ANSWERED AT 20/02/2020 - 09:30 PM


QUESTION POSTED AT 20/02/2020 - 09:30 PM

Triangle XYZ is reflected across the y -axis to form triangle X'Y'Z'. Triangle X'Y'Z' is dilated by a scale factor of 2 to form triangle X”Y”Z” . Which statements correctly describe triangle XYZ, triangle X'Y'Z', and triangle X”Y”Z”. Answer Choices: A. Triangle XYZ is congruent to triangle X'Y'Z'. B. Triangle X'Y'Z' is congruent to triangle X”Y”Z”. C. Triangle XYZ is similar to triangle X”Y”Z”. D. Triangle X”Y”Z” has longer side lengths than triangle XYZ.

⇒ΔXYZ -------Reflected----------ΔX'Y'Z'--------Dilated by a scale factor of 2 to Obtain ------------ΔX"Y"Z".

When two objects are compared ,such that one of which is reflection of other , the two Geometrical shape are Congruent.The Meaning of Congruent is Corresponding Sides as well Corresponding Angles are equal.

So, ΔXYZ≅ΔX'Y'Z'

⇒When One Image is dilation of Other, the two Geometrical shapes are Similar.

When shapes are Similar, Corresponding Sides are Proportional and Corresponding Angles are equal.

 ⇒ ΔXYZ ~ ΔX'Y'Z'

Remember this Property

Congruent shapes are always Similar, but Similar shapes are not always Congruent.

Correct Statements are

Option A: →Triangle XYZ is congruent to triangle X'Y'Z'.

Option C: →Triangle XYZ is similar to triangle X”Y”Z”.

Option D:→Triangle X”Y”Z” has longer side lengths than triangle XYZ.

ANSWERED AT 20/02/2020 - 09:30 PM


QUESTION POSTED AT 20/02/2020 - 09:30 PM

What is the approximate volume of the cylinder? height = 52.2 cm; diameter = 20 cm A. 1640 cm3 B. 3300 cm3 C. 16,400 cm3 D. 65,600 cm3

H = 52.2 diameter = 20 cm
radius = 10 cm
Cylinder volume = π • r² • height
Cylinder volume = PI * 100*52.2

Cylinder volume = 16,399
answer is C

ANSWERED AT 20/02/2020 - 06:05 PM


QUESTION POSTED AT 20/02/2020 - 06:05 PM

The moon is 384,403 km from the Earth. Estimate how many quarters laid end to end it would take to reach the moon if a quarter has a diameter of 2.3 cm.

First, convert 384,403km to cm which is 34840300000 then divide that by 2.3 to get 15147956521.73 but you would need to round up so the answer is about 15147956521.

ANSWERED AT 20/02/2020 - 05:22 PM


QUESTION POSTED AT 20/02/2020 - 05:22 PM